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3 years ago

Please help me for the brainliest answer

Mathematics

1 answer:

olga55 [171]3 years ago

8 0

Answer:

3, 12, 27 and 300

Step-by-step explanation:

Plug n as 1, 2, 3 and 10.

3(1)² = 3

3(2)² = 12

3(3)² = 27

3(10)² = 300

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Which equation shows p(x)= x^6 - 1 factored completely over the integers? (Hint : You will need to use more than one method to c

Fiesta28 [93]

P(x)=(x-1)(x+1)(x^4+x^2+1)

8 0

3 years ago

After spending $30 in a dress, Mary had 3/8 of her money left. How much money did she had first ?

Dennis_Churaev [7]

Answer:

answer is below

Step-by-step explanation:

3/8x(how much money she had)= 30

So, Mary originally had $80.

7 0

3 years ago

Can someone help w this ASAPP!!! Whoever answers correct and quickest ill give brainiest!

butalik [34]

Answer:

8x+8

Step-by-step explanation:

x+4+3x+x+4+3x

8x+8

hope it helps :)

3 0

2 years ago

Read 2 more answers

Henry had $24.12. His friend Greg had one-

Daniel [21]

Answer: $42.21

Step-by-step explanation:

Henry; $24.12

Gregg; $24.12 / 2= $12.06

Kasey; $ 24.12 / 4= $6.03

$24.12 + $12.06 + $6.03

6 0

3 years ago

The attendance at baseball games at a certain stadium is normally distributed, with a mean of 30,000 and a standard deviation of

lakkis [162]

Answer:

a) 0.964

b) 0.500

c) 0.885

d) $x \geq 32467.5$

e) 0.997

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 30000

Standard Deviation, σ = 1500

We are given that the distribution of attendance at stadium is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(attendance is greater than 27,300)

P(x > 27300)

$P( x > 27300) = P( z > \displaystyle\frac{27300 - 30000}{1500}) = P(z > -1.8)$

$= 1 - P(z \leq -1.8)$

Calculation the value from standard normal z table, we have,

$P(x > 27300) = 1 - 0.036 = 0.964 = 96.4\%$

b) P(attendance greater than or equal to 30000)

$P(x > 30000) = P(z > \displaystyle\frac{30000-30000}{1500}) = P(z \geq 0)\\\\P( z \geq 0) = 1 - P(z \leq 0)$

Calculating the value from the standard normal table we have,

$1 - 0.500 = 0.500 = 50\%$

c) P(attendance between 27000 and 32000)

$P(27000 \leq x \leq 32000) = P(\displaystyle\frac{27000 - 30000}{1500} \leq z \leq \displaystyle\frac{32000-30000}{1500}) = P(-2 \leq z \leq 1.33)\\\\= P(z \leq 1.33) - P(z < -2)\\= 0.908 - 0.023 = 0.885 = 88.5\%$

$P(27000 \leq x \leq 32000) = 88.5\%$

e) P(attendance less than 33000)

P(x < 33000)

$P( x < 33000) = P( z < \displaystyle\frac{33000 - 30000}{1500}) = P(z < 2)$

Calculating the value from the standard normal table we have,

P(x < 33000) = 0.997 = 99.7%

d) We have to find x such that:

$P( X > x) = P( z > \displaystyle\frac{x - 30000}{1500}) = 0.95$

Calculating the value from the standard normal table we have,

P(z = 1.645) = 0.95

Thus,

$\displaystyle\frac{x - 30000}{1500} \geq 1.645\\\\x \geq 32467.5$

The attendance should be greater than or equal to 32467.5 to be in the top 5% of all games.

6 0

4 years ago