1] Given that the value of x has been modeled by f(x)=12500(0.87)^x, then:
the rate of change between years 1 and 5 will be:
rate of change is given by:
[f(b)-f(a)]/(b-a)
thus:
f(1)=12500(0.87)^1=10875
f(5)=12500(0.87)^5=6230.3
rate of change will be:
(6230.3-10875)/(5-1)
=-1161.2
rate of change in years 11 to 15 will be:
f(11)=12500(0.87)^11=2701.6
f(15)=12500(0.87)^15=1,547.74
thus the rate of change will be:
(1547.74-2701.6)/(15-11)
=-288
dividing the two rates of change we get:
-288/-1161.2
-=1/4
comparing the two rate of change we conclude that:
The average rate of change between years 11 and 15 is about 1/4 the rate between years 1 and 5.
The answer is D]
2] Given that the population of beavers decreases exponentially at the rate of 7.5% per year, the monthly rate will be:
monthly rate=(n/12)
where n is the number of months
=7.5/12
=0.625
This is approximately equal to 0.65%. The correct answer is A. 0.65%
Answer: 15 miles
Step-by-step explanation:
The equation is 5.25+1.25x=24 where x is each additional mile so to solve for x it would be 1.25x=18.75 and divide both sides to solve for x
X = 5/3 and m∠SPY = 8 1/3°.
Since PQ bisects the angle, the two angles formed by the bisector are equal:
11/2x - 5 = 4x - 5/2
We will first multiply everything by 2 to eliminate the fractions:
(11/2x)*2 - 5*2 = 4x*2 - (5/2)*2
11x - 10 = 8x - 5
Subtract 8x from each side:
11x - 10 - 8x = 8x - 5 - 8x
3x - 10 = -5
Add 10 to both sides:
3x - 10 + 10 = -5 + 10
3x = 5
Divide both sides by 3:
3x/3 = 5/3
x = 5/3
Now we will plug this in for x in both smaller angles and add them together to find the measure of ∠SPY:
11/2(5/3) - 5 + 4(5/3) - 5/2
55/6 - 5 + 20/3 - 5/2
We will rewrite everything using a denominator of 6:
55/6 - 30/6 + 40/6 - 15/6 = (55-30+40-15)/6 = 50/6 = 8 2/6 = 8 1/3°
Sorry I needed points for an important quiz
I’m not *completely* sure if this would be right, but it could possibly be:
160
how i got this:
20 = 150
/(divide) 150
0.13(recurring) = 1
x1200
160 = 1200
if you need me to explain anything in detail, please feel free to message! have a nice day:)<3
