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Oksana_A [137]
3 years ago
8

1 2/3 X 3/4 what is the awnser with work shown

Mathematics
1 answer:
alex41 [277]3 years ago
6 0
First you would have to turn the mixed number into a improper fraction. to do that you would have to multiply the denominator by the 1 (which is the whole number) to get 3*1=3 then you would have to add the numerator to get 3+2=5. now you have an improper fraction which is now 5/3. you always keep the denominator the same. next you have to multiply the two fractions you now have. which is 5 over 3 and 3 over 4 . all you have to do is multiply across to get 5*3=15 on the top and 3*4=12 on the bottom. so your new fraction you have is 15/12. that's an improper fraction so you would have to divide 12 by 15. you know 12 goes into 15 one time with a remainder of 3. so now you have 1 3/12 as your answer. but your not done yet. now you have to simplify your answer by dividing the numerator and denominator by 3 to get 3/3=1 and 12/3=4, you final answer should be 1 1/4 .
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Help pleasee<br> Qn is attached belowww <br> PLEASE HELPP
Simora [160]

Answer:

QR = 65.4 m

Step-by-step explanation:

a. Apply Law of Cosines to find QR:

p² = q² + r² - 2qr × Cos P

p = QR = ?

q = PR = 150 m

r = PQ = 120 m

P = 25°

Plug in the values

p² = 150² + 120² - (2)(150)(120) × Cos(25°)

p² = 22,500 + 14,400 - 36,000 × 0.9063

p² = 36,900 - 32,626.8

p² = 4,273.2

p = √4,273.2

p ≈ 65.4 m (nearest tenth)

QR = 65.4 m

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3 years ago
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Answer: Greater than

Step-by-step explanation: 0.012 is 12 hundreths

0.12 is 12 tenths

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The sum of two numbers is 72 and their difference is 26. find two numbers?
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Answer:

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Step-by-step explanation:

Let s represent the smaller of the two numbers. Then the larger is s+26, and the sum is ...

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Then the larger number is

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The two numbers are 23 and 49.

_____

The reason we wrote the solution this way is to show you that the smaller number is half the difference between the given sum (72) and difference (26). This is the generic solution to a "sum and difference" problem. The smaller number is always half the difference of the give sum and difference. (Similarly, the larger is always half the sum of the given sum and difference.)

That is, the two numbers are always half the sum ± half the difference:

  72/2 ± 26/2 = {36+13, 36-13} = {49, 23}

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