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STALIN [3.7K]
3 years ago
7

Which statements are true about triangle ABC and its translated image, A'B'C'? Check all that apply.

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
4 0
This is the concept of translation;
Given that triangle A (-1,3), B(-1,1), C(3,1) has been translated to A'(2,-1), B'(2,-4), C(6,-4)
the from the diagram we see that the coordinates of the triangle ABC have been moved by 3 units to the right while the y coordinates have been moved by 5 units down to form A',B',C'.
We therefore conclude that the correct statement is:
Triangle ABC has been translated 3 units to the right and 5 units down.


adelina 88 [10]3 years ago
3 0

Answer:

The rule for the translation can be written as T3, –5(x, y).

Triangle ABC has been translated 3 units to the right and 5 units down.


Step-by-step explanation:

Just took the test.

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▹ Answer

<em>n⁸</em>

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n⁶ * n⁵ ÷ n⁴ * n³ ÷ n² * n

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5 0
3 years ago
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Leokris [45]
1) incorrect
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5 0
1 year ago
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GarryVolchara [31]
See the answer in the image

4 0
2 years ago
The value 5 is an upper bound for the zeros of the function shown below. f(x)=x^4+x^3 -11x^2-9x+18
Inessa [10]
Answer: True

Explanation:
According to the rational zeros theorem, if x=a is a zero of the function f(x), then f(a) = 0.

Given:  f(x) = x⁴ + x³ - 11x² - 9x + 18
From the calculator, obtain
f(5) = 448
f(4) = 126
f(3) = 0
f(2) = -20
f(1) = 0
f(0) = 18
f(-1) = 16
f(-2) = 0
f(-3) = 0

The polynomial is of degree 4, so it has at most 4 real zeros.
From the calculations, we found all 4 zeros as x = -3, -2, 1, and 3.
Therefore
f(x) = (x+3)(x+2)(x-1)(x-3).

For x>3, f(x)increases rapidly. Therefore there are no zeros for x>3.
The statement that x=5 is an upper bound for the zeros of f(x) is true.



7 0
3 years ago
Read 2 more answers
3. What is the area of the triangle below? Round your
Jobisdone [24]

Answer is A because when you work it out the area is 110.500 and rounding it makes it -

8 0
3 years ago
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