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olga55 [171]
3 years ago
14

Resolva c ) 7815+427+2368+864

Mathematics
2 answers:
Mice21 [21]3 years ago
6 0
The answer to your question is 11,474
FromTheMoon [43]3 years ago
6 0
Answer 11474.
This is so easy how do u not know
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Find the volume of a rectangle box 12cm by 15cm by 10cm
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Answer:

Step-by-step explanation:

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5x + 14 = K solve for K
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 Flip the equation.<span>k=<span><span>5x</span>+<span>14</span></span></span>
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2.Draw a diagram to represent each of these situations. Then write an addition expression that represents the final temperature.
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The perimeter of a rectangle is 96cm its shortest side has a length of 5cm state the length of the longest side​
Rainbow [258]

Answer:

43cm

Step-by-step explanation:

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4 0
2 years ago
How many permutations are there of the letters in the words (a) TRISKAIDEKAPHOBIA (fear of the number 13)? (b) FLOCCINAUCINIHILI
zubka84 [21]

Answer: Hello!

Let's start with the word TRISKAIDEKAPHOBIA wich has 17 letters (some of them repeat, but it does not matter in this problem)

We want to know how many permutations we can do with 17 letters: then think this way, Lets compose a word. The first letter of this word has 17 options, the second letter of the word has 16 options (you already took one of the set) the third letter of the word has 15 options, and so on.

The total number of permutations is the product of the number of options that you have for each letter, this is:

17*16*15*14*....*3*2*1 = 17! = 3.6e+14

(b) FLOCCINAUCINIHILIPILIFICATION now we have 30 letters in total, using the same reasoning as before, here we have 30! permutations; this is

30! = 2.65e+32

(c) PNEUMONOULTRAMICROSCOPICSILICOVOLCANOCONIOSIS: now there are 47 letters.

then P = 47! = 2.59e+59

(d) DERMATOGLYPHICS: here are 18 letters, then:

p = 18! = 6.4e+15

6 0
3 years ago
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