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3 years ago

There is more than 1 answer and I already know 1 answer which is 3/4 but I don't know the rest. Please help!

Mathematics

1 answer:

andriy [413]3 years ago

3 0

Answer:

9/12

Step-by-step explanation:

3/4 times 3 = 9/12

3/4 is equivalent to 9/12 so those would be the two anwsers

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4. Use the diagram below to answer the question

ludmilkaskok [199]

Answer:

≈ 397 m

Step-by-step explanation:

Using Pythagoras' identity on the right triangle

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

Let h represent the height of the balloon above ground, then

h² + 50² = 400², that is

h² + 2500 = 160000 ( subtract 2500 from both sides )

h² = 157500 ( take the square root of both sides )

h ≈ 397 m ( to the nearest metre )

4 0

3 years ago

the Shanghai maglev train is one of the fastest trains in the world traveling about 2144 miles and 8 hours how many miles does i

rusak2 [61]

It travels 2144 in 8 hours.

Therefore, if you want to find out how many miles it travels in one hour, divide 2144 by 8.

2144 ÷ 8 = 268 miles in one hour. :)

8 0

3 years ago

What is the volume of a rectangular prism with length 6 mm, height 5 mm, and width 11 mm? V = lwh A. 330 mm B. 330 mm2 C. 330 mm

shepuryov [24]

The answer is 330mm3

3 0

4 years ago

Which equation is the inverse of y= 2x2-8

Xelga [282]

It'd be too hard to comment the answer but here, lemme know if you aren't able to se it

8 0

3 years ago

Read 2 more answers

Refer to the random sample of customer order totals with an average of $78.25 and a population standard deviation of $22.50. a.

zysi [14]

Answer:

a) $78.25- 1.64 \frac{22.50}{\sqrt{40}}= 72.416$

$78.25+ 1.64 \frac{22.50}{\sqrt{40}}= 84.084$

b) $78.25- 1.64 \frac{22.50}{\sqrt{75}}= 73.989$

$78.25+ 1.64 \frac{22.50}{\sqrt{75}}= 82.511$

c) For this case when we increase the sample size the margin of error would be lower and then the interval would be narrower

d) $ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

Solving for n we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

And replacing the info we have:

$n=(\frac{1.640(22.50)}{5})^2 =54.46 \approx 55$

Step-by-step explanation:

Part a

For this case we have the following data given

$\bar X = 78.25$ represent the sample mean for the customer order totals

$\sigma =22.50$ represent the population deviation

$n= 40$ represent the sample size selected

The confidence level is 90% or 0.90 and the significance level would be $\alpha=0.1$ and $\alpha/2 = 0.05$ and the critical value from the normal standard distirbution would be given by:

$z_{\alpha/2}=1.64$

And the confidence interval is given by:

$\bar X -z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$78.25- 1.64 \frac{22.50}{\sqrt{40}}= 72.416$

$78.25+ 1.64 \frac{22.50}{\sqrt{40}}= 84.084$

Part b

The sample size is now n = 75, but the same confidence so the new interval would be:

$78.25- 1.64 \frac{22.50}{\sqrt{75}}= 73.989$

$78.25+ 1.64 \frac{22.50}{\sqrt{75}}= 82.511$

Part c

For this case when we increase the sample size the margin of error would be lower and then the interval would be narrower

Part d

The margin of error is given by:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

Solving for n we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

And replacing the info we have:

$n=(\frac{1.640(22.50)}{5})^2 =54.46 \approx 55$

3 0

3 years ago