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saw5 [17]
3 years ago
13

(6x) to the power of the second

Mathematics
2 answers:
jolli1 [7]3 years ago
6 0
(6x)^2=36x^2
Damm [24]3 years ago
5 0
(Apparently this needs 20 characters to explain it will, so have this type.)
(6x)^2 = 36x^2
6*6=36
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WILL GIVE BRAINLIEST! Find the equation of a line that passes through (-5,-2) and the intersection of the lines x+3y=0 and 4x-4y
Verdich [7]

Answer:

y + 2 = -0.069(x-+5)

Step-by-step explanation:

SInce the two lines intersects, we will equate it

Multiply x + 3y = 0 by 4;

4x + 12y = 0

4x-4y-13 = 0,

Subtracts both

12y +4y + 13 = 0

16y = 13

y = 13/16

get x;

x + 3(13/16) = 0

x = -39/16

The point of intersection is (0.8, -2.4) and (-5,-2)

Get the equation;

m = y2-y1/x2-x1

m = -2+2.4/-5-0.8

m = 0.4/-5.8

m = -0.069

Get the equation;

y - y0 = m(x-x0)

y - (-2)= -0.069(x-(-5))

y + 2 = -0.069(x-+5)

6 0
2 years ago
If y varies directly with x, find the value of x when y is 180 and k is 15.
BabaBlast [244]
A

Divide 180 over 15
6 0
3 years ago
Read 2 more answers
Consider the following incomplete mapping diagrams.
zlopas [31]

Answer:

Answer attached

Step-by-step explanation:

3 0
3 years ago
“Write an equation in standard form of the horizontal line that goes through (-7, 10)”
OlgaM077 [116]

Answer:

Step-by-step explanation:

A horizontal line is only concerned with the y value. The equation is y = 10 because that is the point that the line must go through.

The x value does not matter as long as the y value is given as 10. The domain is any real value. The range is 10

6 0
3 years ago
Two 120 resistors are connected in parallel across voltage supply of 10 vdc what’s the current in this circuit
Daniel [21]

Answer: 0.167

Step-by-step explanation:

This is an applied mathematics question

Resistors in parallel  ⁾/R = ¹/₁₂₀ + ¹/₁₂₀ since the resistor is two 120

Therefore , resolve into fraction now yield

                       ¹/R                              =         1 + 1  

                                                                    -------

                                                                     120

                                                          =         2/120

                                                          =          ¹/₆₀

Therefore,                                  ¹/R   =      ¹/₆₀

 Cross multiply to get R the resistance

                                                      R  =  60

From formula,                                V = IR where I is the current

There fore making I the subject of the formula

                                                        I = V/R

                                                          = 10/60

                                                          = 0.166

                                                          = 0.167 A, A = ampere which is the unit of current.

                   

4 0
3 years ago
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