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3 years ago

In △ABC, m∠A=19°, a=13, and b=14. Find c to the nearest tenth.

1 answer:

34kurt3 years ago

3 0

We know that
Applying the law of sines

step 1
Find the value of angle B
a=13
b=14
A=19°
so

$\frac{a}{sin A} = \frac{b}{sin B} \\ a*sin B=b*sin A \\ sin B= \frac{b}{a}*sin A \\ sin B= \frac{14}{13} *sin 19 \\ sin B=0.3506 \\ B=arc sin(0.3506) \\ B=20.5$ °

step 2
with angle A and angle B find the angle C
A+B+C=180-----> solve for C
C=180-(A+B)------> C=180-(19+20.5)-----> C=140.5°

step 3
$\frac{a}{sin A} = \frac{c}{sin C} \\ a*sin C=c*sin A \\ c=a* \frac{sin C}{sin A} \\ c=13* \frac{sin 140.5}{sin 19} \\ c=25.4$

the answer is
the value of c is 25.4

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yulyashka [42]

First we need to know the coordinates of the movie theater, we can do this applying the midpoint formula:

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1 year ago

if the sum of the first 60 positive integers is s, what is the sum of the first 120 integers in terms of s? a. 2s 3600 b. s^2 36

kvasek [131]

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2 years ago

Find the area between the two functions

Inga [223]

The area between the two functions is 0

<h3>How to determine the area?</h3>

The functions are given as:

f₁(x)= 1

f₂(x) = |x - 2|

x ∈ [0, 4]

The area between the functions is

A = ∫[f₂(x) - f₁(x) ] dx

The above integral becomes

A = ∫|x - 2| - 1 dx (0 to 4)

When the above is integrated, we have:

A = [(|x - 2|(x - 2))/2 - x] (0 to 4)

Expand the above integral

A = [(|4 - 2|(4 - 2))/2 - 4] - [(|0 - 2|(0 - 2))/2 - 0]

This gives

A = [2 - 4] - [-2- 0]

Evaluate the expression

A = 0

Hence, the area between the two functions is 0