1. We have to find the fifth term of f(n) = 7 - 4(n - 1).
That means x = 5. Substitute 5 into the equation for x.
f(n) = 7 - 4(5 - 1)
Subtract 5 - 1.
f(n) = 7 - 4(4)
Multiply 4 by 4.
f(n) = 7 - 16
Subtract 16 from 7.
f(n) = -9
The answer is D.
2. Since we have to find the first 4 terms, we have to solve for x = 1, 2, 3, & 4.
Multiply 1, 2, 3, and 4 by 6. We now have:
f(x) = 6 - 25 f(x) = 12 - 25 f(x) = 18 - 25 f(x) = 24 - 25
Subtract 25 from the first term: 6, 12, 18, and 24.
f(x) = -19 f(x) = -13 f(x) = -7 f(x) = -1
The answer is C.
3. Now, we have to find the first 3 terms of f(x) = 10(2)^x. So x is 1, 2, & 3.
Raise 2 to the powers of 1, 2, and 3. The equations are now:
f(x) = 10(2) f(x) = 10(4) f(x) = 10(8)
Then multiply 10 by the three terms: 2, 4, and 8.
f(x) = 20 f(x) = 40 f(x) = 80
The answer is A.
4. Find the 21st term of f(n) = 2 + 9(n - 1). Substitute 21 for n.
f(n) = 2 + 9(21 - 1)
Subtract 1 from 21.
f(n) = 2 + 9(20)
Multiply 9 by 20.
f(n) = 2 + 180
Add 2 to 180.
f(n) = 182
The answer is B.
5. Which sequence is described by f(n) = 2(3)^x-5.
This is the only one which I'm not sure how to solve. Since I don't know, I won't answer it because I don't want to give you the wrong answer to the question, sorry about that.
6. The ninth term in f(n) = 384(1/2)^n-1. Put 9 in for n & subtract 1 from 9.
f(n) = 384(1/2)^8
Raise 1/2 to the power of 8.
f(n) = 384(1/256)
Multiply 1/256 by 384.
f(n) = 384/256
Reduce the fraction & make it a mixed number.
f(n) = 1 1/2
Hope this helped!
Answer:
If it is, identify a success, specify the values of n, p, and q, and list the possible values of the random variable x. If it is not a binomial experiment, explain why. You darw 5 cards one at a time from a standard deck you do not replace a card once it is drawn. The
In this problem, we can imagine that all the points
connect to form a triangle. The three point or vertices are located on the
pitcher mount, the home plate and where the outfielder catches the ball. So in
this case we are given two sides of the triangle and the angle in between the
two sides.
<span>With the following conditions, we can use the cosine law
to solve for the unknown 3rd side. The formula is:</span>
c^2 = a^2 + b^2 – 2 a b cos θ
Where,
a = 60.5 ft
b = 195 ft
θ = 32°
Substituting the given values:
c^2 = (60.5)^2 + (195)^2 – 2 (60.5) (195) cos 32
c^2 = 3660.25 + 38025 – 20009.7
c^2 = 21,675.56
c = 147.23 ft
<span>Therefore the outfielder throws the ball at a distance of
147.23 ft towards the home plate.</span>
6
think of this as the middle.
3 to the left to get to 3
And
3 to the right to get 9
