Y=mx+b
m=slope
given
y=4x+5
m=4=slope
2.
for the points (x1,y1) and (x2,y2), the slope of the line passing trhough those points is (y2-y1)/(x2-x1)
given
(1,6) and (3,10)
slope=(10-6)/(3-1)=4/2=2
function 1 slope is 4
function 2 slope is 2
4>2
the first one has greater rate of change
4x - y = 5 --> 4x = y + 5
substitute
4x + 4y = -4
(y + 5) + 4y = -4
5y + 5 = -4
5y = -9
y = -1.8
solve x
4x = y + 5 = -1.8 + 5 = 3.2
x = 3.2/4 = 0.8
Answer:
0.50 kg of the material would be left after 10 days.
0.25 kg of the material would be left after 20 days.
Step-by-step explanation:
We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.
We will use half life formula.
, where,
A = Amount left after t units of time,
a = Initial amount,
t = Time,
h = Half-life.
Therefore, amount of the material left after 10 days would be 0.5 kg.
Therefore, amount of the material left after 20 days would be 0.25 kg.
Answer:
+8
Step-by-step explanation:
Answer:
1
Step-by-step explanation:
The amplitude is the maximum distance away from the middle of the wave. Here we can see that the middle of the wave is the x axis and the farthest point (largest difference between the y coordinate of the x-axis, or the line y = 0, and the wave) is 1 unit away.