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Alona [7]
4 years ago
10

A marketing firm is studying consumer preferences for winter fashions. From a population of women aged 18 to 21 years, a random

sample of 100 women was selected in the month of January. Three more similar random samples were conducted during the months of March, June, and September. What is the number of samples?
Mathematics
1 answer:
sergeinik [125]4 years ago
4 0

Answer:

we say the number of samples is 4

Step-by-step explanation:

Given data

sample = 100

total sample conduct = 4 time

to find out

What is the number of samples

solution

we know that sample size for each month is 100

4 time sample taken January, march, June and September.

so that no of people sample is = 4 × 100 = 400

so that for number is sample is 400 /100

so we say the number of samples is 4

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Linear equation of plant height is h = (1/2)w + 3

Given:

Height of experimental plant = 3cm

Average growth = 0.5 cm per week

Find:

Linear equation of plant height

Computation:

Given;

h = Plant height

w = number of weeks

So,

Plant height = Height of experimental plant + (Average growth)(number of weeks)

h = 3 + (0.5)(w)

h = (1/2)w + 3

Option "J" is the correct answer to the following question.

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3 0
2 years ago
I dont know the x of 30-2x=22
zloy xaker [14]

Answer:

4

Step-by-step explanation:

30-22=2x

8=2x

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3 0
3 years ago
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Notah lives in Minnesota. He records the lowest temperature each day for one week. What is the mean of the temperatures? -7.3°F,
natita [175]

Answer:

-2.1

Step-by-step explanation:

-7.3 - 11.2 - 1.7 + 0 + 0 +2.2 + 3.3

--------------------------------------------------

                            7

= -2.1

4 0
3 years ago
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The point (5, -1) is a solution of the equation: y = 2x − 11 question 28 options: true false
kkurt [141]
True
This is because on replacing for x=5;
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8 0
4 years ago
Can someone help me?
Lana71 [14]

Answer:

I'm not sure from my answer but I'm going to try

A =  { a^2  -  4  = 0 }

A = { a^2  = 0+ 4 }

A = { a^2  = 4}

Take root of both sides

A = {a = 2}

A = {2}

B = { -2, -1, 0, 1, 2}

C = { 1, 2, 3, 4, 5, 6,7}

i) A\B

= {2} \ {-2,-1,0,1,2}

= ⌀ ( "null set" )

ii) (A\B) \C

= ( {2} \ {-2,-1,0,1,2} ) \ C

= ⌀ \ C

= ⌀ \ { 1, 2, 3, 4, 5, 6,7}

= ⌀ ( "null set" )

iii) (A ∪ B) \ C

= ( { 2 } ∪ { -2, -1, 0, 1, 2} ) \ C

= { -2, -1, 0, 1, 2} \C

= { -2, -1, 0, 1, 2} \ { 1, 2, 3, 4, 5, 6,7}

= { -2, -1, 0 }

iv) ( A\B) ∩ ( A\C)

= (  { 2 } \ {-2,-1,0,1,2} ) ∩ ( { 2 } \ { { 1, 2, 3, 4, 5, 6,7} )

= ⌀ ∩ ⌀

= ⌀

v) ( A ∩ B ) \ C

= ( { 2 }  ∩  { -2, -1, 0, 1, 2 } ) \ C

= { 2 } \ { 1, 2, 3, 4, 5, 6, 7 }

= ⌀ "null set"

7 0
3 years ago
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