In the following triangle, find the values of the angles B and B', which are the best approximations to the solutions of this am
biguous case.
2 answers:
Answer:
Option B. B = 70.05° B' = 109.95°
Step-by-step explanation:
By the sine rule in a given triangle
sin 45°/16.5 = sinB/22
1/(1.414×16.5) = sinB/22
sinB = 22/(1.414×16.5) = 0.94
B = 70.05°
Now we know B' = 180 - Supplementary angle of B'
and B = B' ( opposite angles of equal sides are equal)
B' = 180 - B = 180 - 70.05 = 109.95°
Therefore option B is the answer.
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Answer:
Option A
Step-by-step explanation:
This is a great question!
The first thing we want to do here is to graph the system of " inequalities " -
As x is ≥ 0, respectively y ≥ 0, it makes things a lot simpler, as it kind of restricts us to quadrant 1, but not entirely.
First change each inequality to " slope - intercept " form, as such -
The graphed solutions would be in the attachment. I have colored the region with which the two intersect, and the fact that we are limited to quadrant 1. In this colored region there are 3 major points, ( 5, 9 ), ( 0, 10 ), and ( 6, 0 ). We have to determine which of these are are maximum points, as the minimum are the same. Substitute these values ( ( 5, 9 ), ( 0, 10 ), and ( 6, 0 ) ) into the equation f( x, y ) = 10x + 4y,
( 5, 9 ) resulted in the greatest amount, 86. That would make it our maximum point -
<u><em>Solution = Option A</em></u>
