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Reil [10]
3 years ago
11

-4+(-3) help please thanks

Mathematics
2 answers:
madreJ [45]3 years ago
6 0
-7 is correct because a negative plus a negative is always a negative
Bingel [31]3 years ago
6 0
-4+(-3)=-7

When adding two negatives, the answer will always be negative. I hope this helps.
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HELP PLS! <br> Solve (x-5)^2=3
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Answer:

Step-by-step explanation:Use the square root on both sides:

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7 0
3 years ago
Prove each of these identities.
Stella [2.4K]

Answer:

Identity (a) can be re-written as

sec x\ cosec x  - cot x = tan x

which we already proven in another question, while for idenity (b)

(A)\frac 1 {sin x} -sin x = cos x \frac{cos x}{sin x}\\\\(B)\frac {1-sin^2x}{sin x} = \frac {cos^2x} {sin x} \\\\(C) \frac {cos^2x}{sin x} =\frac {cos^2x} {sin x}

step A is simply expressing each function in terms of sine and cosine.

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step C is replacing the term on the numerator with the equivalent from the pithagorean identity cos^2x  + sin^2x = 1

8 0
2 years ago
A number y is no more than −8.<br><br> help me
PolarNik [594]

Answer:

y <= -8

Step-by-step explanation:

This algebraic expression would read as:

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7 0
3 years ago
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Given that ABCD~JKLM <br> find the ratio of the perimeter of ABCD to JKLM
Westkost [7]

Answer:

The ratio of the perimeter of ABCD to JKLM is;

b. 3/5

Step-by-step explanation:

Given that ABCD ~ JKLM, where;

DC and ML are corresponding sides

AD and JM are corresponding sides

AB and JK are corresponding sides

Therefore;

DC/ML = AD/JM = AB/JK

Plugging in the values of the variables gives;

9/15 = z/10 = x/12

∴ z = 10×9/15 = 6

x = 12×9/15 = 7.2

9/15 = 6/y

y = 6 ×15/9 = 10

The perimeter of the quadrilateral ABCD = AB + BC + DC + AD

∴ The perimeter of the quadrilateral ABCD = 6 + 6 + 9 + 7.2 = 28.2

The perimeter of the quadrilateral JKLM = JK + JM + ML + LK

∴ The perimeter of the quadrilateral JKLM = 12 + 10 + 15 + 10 = 47

The ratio of the perimeter of ABCD to JKLM = 28.2/47 =0.6 = 3/5.

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3 years ago
Select the correct answer.
Fudgin [204]
A) an answer that cannot be written as a fraction.
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