3 years ago

Choosing a number divisible by 3

Mathematics

1 answer:

sergejj [24]3 years ago

4 0

Answer:

9 or 6 owo

Step-by-step explanation:

uwu

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Edit to reflect comments:

3^-1=1/3
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(0,0)

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The quadratic fomula:

$ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\If\ \Delta0,\ then\ \boxed{TWO\ SOLUTIONS:\ x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}}-----------------------------------------------$

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$2x^2-7x-21=0\\\\a=2,\ b=-7,\ c=-21\\\\\Delta=(-7)^2-4(2)(-21)=49+168=217 > 0\\\\x_1=\dfrac{-(-7)-\sqrt{217}}{2(2)}=\dfrac{7-\sqrt{217}}{4}\approx-1.93\\\\x_2=\dfrac{-(-7)+\sqrt{217}}{(2)(2)}=\dfrac{7+\sqrt{217}}{4}\approx5.43\\\\Answer:\ \boxed{\boxed{2.\ -1.93\ and\ 5.43}}$

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Find the amount accumulated after investing a principle P for T years at an interest rate compounded k times per year.

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3 years ago

Choosing a number divisible by 3​

Choosing a number divisible by 3