It number A i got it right and ill show you it
Yasim is Albert who ran the race at a time that was 15.7 seconds shorter, So, Yasim is the student who improved the most by decreasing the time needed to run the race.
<h2>Given that,</h2>
Coach Burns charted the change in his runners' 5K times from the first race of the year to the second race of the year.
<h3>We have to
find,</h3>
Which student improved the most by decreasing the time needed to run the race?
<h3>
According to the
question,</h3>
Coach Burns charted the change in his runners' 5K times from the first race of the year to the second race of the year.
In the given option Yasim has the lowest value of the time which is -37.5 seconds.
Yasim was the most improved student because Yasim ran the second race in a time that was 37.4 seconds shorter than the first race.
Following Yasim is Albert who ran the race at a time that was 15.7 seconds shorter.
At the third place in improvement is Cody who actually was worse off than the first race along with the 4th place Hannah.
Hence, Yasim students improved the most by decreasing the time needed to run the race.
For more details about the Equation refer to the link given below.
brainly.com/question/3842749
I count n=12 observations, sorted they're
0 0 0 1 1 2 2 3 3 4 5 10
The median is the middle value, or the average of the two middle ones when we have an even number. That's (2+2)/2=2
Median: 2
The mode is the most common observation. Three friends had no pets.
Mode: 0
The range is maximum minus minimum, so 10 - 0 = 10
Range: 10
Answer:
T = -7 + 3t .
Step-by-step explanation:
T = -7 + 3t where T = the temperature and t = the times in hours.
