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Shkiper50 [21]
3 years ago
10

What is the value of x in units

Mathematics
2 answers:
nikdorinn [45]3 years ago
6 0

\triangle RQT\ \text{and}\ \triangle SRT\ \text{are similar. Therefore the sides are in proportion.}\\\\\dfrac{RT}{TQ}=\dfrac{TS}{RT}\\\\\text{We have}\ RT=x,\ TQ=16,\ TS=9.\ \text{Substitute:}\\\\\dfrac{x}{16}=\dfrac{9}{x}\qquad\text{cross multiply}\\\\x^2=(9)(16)\\\\x^2=144\to x=\sqrt{144}\\\\\boxed{x=12}

castortr0y [4]3 years ago
3 0
The value of x in units would be 8 I could be completely wrong though
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Write the x-intercept of the graph of -6x + y = 8.
Trava [24]

Answer:

x-intercept:  x = -4/3

Step-by-step explanation:

x-intercept when y = 0

-6x + 0 = 8

so

-6x = 8

x = 8/-6

x = -4/3

6 0
3 years ago
Which equations represent exponential growth? Which equations represent exponential decay? Drag the choices into the boxes to co
Norma-Jean [14]

Answer:

Exponential growth functions are:

A=20000(1.08)^{t}

A=40(3)^{t}

A=1700(1.07)^{t}

Exponential decay functions are:

A=80(\frac{1}{2})^{t}=80(0.5)^{t}

A=1600(0.8)^{t}

A=1700(0.93)^{t}

Step-by-step explanation:

Given:

An exponential function is of the form y=ab^{x}, where, a\ne 0.

Now, if a > 0 and b > 1, then the exponential function represent exponential growth.

If a > 0 and 0 < b < 1, then the exponential function represent exponential  decay.

Let us check each function now.

Option 1: A=20000(1.08)^{t}

Here, a = 20000, b = 1.08

As 1.08 > 1, the function is exponential growth.

Option 2: A=80(\frac{1}{2})^{t}=80(0.5)^{t}

Here, a = 80, b = 0.50

As 0.5 < 1, the function is exponential decay.

Option 3: A=1600(0.8)^{t}

Here, a = 1600, b = 0.8

As 0.8 < 1, the function is exponential decay.

Option 4: A=40(3)^{t}

Here, a = 40, b = 3

As 3 > 1, the function is exponential growth.

Option 5: A=1700(1.07)^{t}

Here, a = 1700, b = 1.07

As 1.07 > 1, the function is exponential growth.

Option 6: A=1700(0.93)^{t}

Here, a = 1700, b = 0.93

As 0.93 < 1, the function is exponential decay.

5 0
3 years ago
Question 9 20% of a particular brand of light bulbs fail in one year. What is the probability that three bulbs out of a random c
Delvig [45]

Answer:

The correct answer is 0.15

Step-by-step explanation:

According to the given scenario, the probability is as follows:

X\sim Bin (n,p)

Here

n = 8

p = 0.20 or 20%

Now this is a binomial probability distribution

P(X) = ^nC_x \times p^x \tmes (1 - p)^{n-x}\\\\P(3) = ^8C_3 \tims 0.20^3 \times (1 - 0.20)^5

= 0.15

Hence, the correct answer is 0.15

5 0
2 years ago
Brian rides his bicycle 24 miles in 2 hours. Write a ratio of Brain's miles per hour. Use the ratio from #1 to determine how far
Sati [7]

Answer:Ratio in miles per hour is 12 miles per hour.

Distance travelled is 60miles

Step-by-step explanation:

Speed=distance/time taken

24/2=12miles per hour

Therefore, distance travelled in 5 hours is 12*5=60miles

6 0
3 years ago
Consider the function g(x) = 10/x
ss7ja [257]
<span><span>The correct answers are:
</span><span>(1) The vertical asymptote is x = 0
(2) The horizontal asymptote is y = 0

</span><span>Explanation:
</span><span>(1) To find the vertical asymptote, put the denominator of the rational function equals to zero.

Rational Function = g(x) = </span></span>\frac{10}{x}<span>

Denominator = x = 0

Hence the vertical asymptote is x = 0.

(2) To find the horizontal asymptote, check the power of x in numerator against the power of x in denominator as follows:

Given function = g(x) = </span>\frac{10}{x}<span>

We can write it as:

g(x) = </span>\frac{10 * x^0}{x^1}<span>

If power of x in numerator is less than the power of x in denomenator, then the horizontal asymptote will be y=0.
If power of x in numerator is equal to the power of x in denomenator, then the horizontal asymptote will be y=(co-efficient in numerator)/(co-efficient in denomenator).
If power of x in numerator is greater than the power of x in denomenator, then there will be no horizontal asymptote.

In above case, 0 < 1, therefore, the horizontal asymptote is y = 0
</span>
5 0
3 years ago
Read 2 more answers
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