Maybe another day in the life of who knows what im talking about
Yes, the line can be used to make reasonable predictions of the number of cheese pizzas that would be sold in the upcoming weeks. This is because the line is the line of best fit
<h3>Line of best fit </h3>
From the question, we are to determine if the line can be used to make reasonable predictions of the number of cheese pizzas that would be sold in the upcoming weeks
In the graph, we have a scatterplot.
The line drawn is the <u>line of best fit</u>
Hence,
Yes, the line can be used to make reasonable predictions of the number of cheese pizzas that would be sold in the upcoming weeks. This is because the line is the line of best fit.
Learn more on Line of best fit here: brainly.com/question/1564293
#SPJ1
Assuming the vertex of the triangle shown is the center of the pentagon, and the line segment shown is an altitude of the triangle:
If we join the center of (the circumscribed circle and of) the pentagon to the 5 vertices, 5 isosceles triangles are formed, all congruent to the one shown in the figure. It is clear that these triangles are congruent, so to find the area of the pentagon, we find the area of one of these triangles and multiply by 5.
The base of the triangle is 22.3 in, and the height is 15.4 ins, thus the area of the pentagon is:
5(Area triangle)=5*[(22.3*15.4)/2]=<span>858.55 (square inches).
Answer: </span>858.55 (square inches).
Answer:
The correct option is (A).
Step-by-step explanation:
The equation for the Estimated Energy Requirement (EER) of 19 or more years older men is:
Here,
AGE = age counted in years
PA = appropriate physical activity factor
WT = weight in kilograms
HT = height in meters
The physical activity factor for men and women is:
Activity Level PA (men) PA (Women)
Sedentary 1.00 1.00
Low 1.11 1.12
Active 1.25 1.27
Very Active 1.48 1.45
Given:
AGE = 22 year-old male college student
PA = low = 1.11
WT = 180 pounds = 81.6466 kg
HT = 5'10" = 1.778 m
Compute the value of EER as follows:
Thus, the EER for a 22-year-old male college student is approximately 2962 kcal.
The correct option is (A).
