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3 years ago

The scale factor is 3:1 what would y and x be ? Having a hard time trying to figure this out

Mathematics

1 answer:

Ainat [17]3 years ago

6 0

$\dfrac{3}{1} = \dfrac{30}{y}$

Cross multiply:
$3y = 30$

Divide by 3:
$y = 10$

Answer: y = 10

$\dfrac{3}{1} = \dfrac{x}{8}$

Cross multiply: $x = 24$

Answer: x = 24

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Mr. Gage wants to buy a new car A but is considering used Car B. Car A costs $2,500 less than twice as much as car B. If car A c

Sergeeva-Olga [200]

1250 is the answer simple math.

4 0

3 years ago

Read 2 more answers

Ian land 2/5 of a mile and walked 16/20 of a mile while returning home from school which pair of equivalent fractions can be use

Anarel [89]

Answer:

2/5: 4/5

Step-by-step explanation:

2/5 of a mile : 16/20 of a mile

It can be made equivalent in 2 ways. Either make the first fraction equivalent by multiplying it with 4 or make the second fraction equivalent to the first by dividing it by 4

2*4/5*4: 16/20

= 8/20: 16/20

2. 2/5: 16/4/20/4

= 2/5: 4/5

It is better to choose a smaller fraction as they are easy to solve .

So the total distance he covered = 2/5+ 4/5= 6/5= 1 1/5 miles or 1.20 miles from school to home.

4 0

3 years ago

Question 1,2, and 3 how do i factor those? Can you show the work and explain how?

DiKsa [7]

1: $3n^{2}+9n+6$

notice that each part is divisible by 3

$3n^{2}$ ÷ 3 = $n^{2}$

9n ÷ 3 = 3n

6 ÷ 3 = 2

so it becomes $3(n^{2} +3n+2)$

3n can be rewritten as 2n+n

-you want to rewrite it into two numbers that multiply to the number that's alone (in this case 2)

which would get you

$3(n^{2} +2n+n+2)$

Now that it's rewritten, you can factor out n + 2 from the equation.

the answer is

3(n+2)(n+1)

And you can check that by multiplying (n+2)(n+1) which is $n^{2} +2n+n+2$ and then each of those by 3, which is $3n^{2} +6n+3n+6$ or $3n^{2}+9n+6$ , our origional equation

2: $28+x^{2} -11x$

So I rewrote this as $x^{2} -11x+28$ (it's the same thing, just reordered using the commutative property)

now -11x can be rewritten as -4x-7x

(remember, the two numbers should multiply to equal 28, which is our constant.)

$x^{2} -4x-7x+28$

now we can factor out x from the first expression and -7 from the second

$x(x-4)-7(x-4)$

and lastly you factor out x-4,

which would give you

(x-4)(x-7)

Make sure to check your work and make sure it multiplies to $x^{2} -11x+28$

3: $9x^{2} -12x+4$

The first thing I notice when looking at this problem is that both 9 and 4 are perfect squares. Not only that, but they are the squares of 2 and 3, which are products of -12

So if you rewrite 9 as $3^{2}$ and 4 as $2^{2}$ , the equation becomes

$3^{2} x^{2} -12x+2^{2}$

now that $3^{2} x^{2}$ is ugly so it can be turned into $(3x)^{2}$

and -12x can be rewritten as $-2*3x*2$

so our equation now looks like $(3x)^2-2*3x*2+2^{2}$

There's a rule that says $a^{2} -2ab+b^{2} = (a-b)^{2}$

In our case, a=3x and b=2

so the final answer is

$(3x-2)^2$

5 0

3 years ago

X+y-3z=8 Slove for x

bagirrra123 [75]

ANSWER:

x= −y + 3z +8

7 0

3 years ago

Read 2 more answers

If A=[xy5−8] determine the values of x and y for which A2=A.

Ivanshal [37]

Answer:

Step-by-step explanation:

Given the 2 by 2 matrix $A = \left[\begin{array}{-cc}x&5\\y&-8\\\end{array}\right]$ , we are to find the value of x and y for the expression A² = A to be true.

First we need to find A² by multiplying the same matrix together

$A^2 = \left[\begin{array}{-cc}x&5\\y&-8\\\end{array}\right] \left[\begin{array}{-cc}x&5\\y&-8\\\end{array}\right]\\\\ \ we \ normally \ multiply \ the \ rows \ of \ the \ first \ matrix \ with \ the \ column \ of \ the \ second \\\\A^2 = \left[\begin{array}{-cc}x^2+5y&5x-40\\xy-8y&5y+64\\\end{array}\right]\\\\Since \ A^2 = A,\ hence;\\\\\left[\begin{array}{-cc}x^2+5y&5x-40\\xy-8y&5y+64\\\end{array}\right] = \left[\begin{array}{-cc}x&5\\y&-8\\\end{array}\right]\\$

Equating the first row and second column of both matrices together, we will have;

5x-40 = 5

add 40 to both sides of the equation

5x-40+40 = 5+40

5x = 45

x = 45/5

x = 9

Similarly, we will equate the second row and second column of both matrices to have;

5y+64 = -8

Subtract 64 from both sdies

5y+64-64 = -8-64

5y = -72

y = -72/5

Hence the value of x is 9 and y is -72/5

7 0

3 years ago