Answer:
Okay I'm not thoroughly understanding your question. But here is my answer for BOTH ways.
Step-by-step explanation:
If it's 5 TIMES 3x/8 +2=7
x= 8/3 or x=2.6
If it's 5(3x) OVER 8 in fraction form +2=7
x= 11
Hope this answers your question.
Answer: 224 students own a school sweatshirt.
Step-by-step explanation:
40% of 560 means 60% do not have one
0.60 is 60% as a decimal
560 x 0.60 = 336 students without a sweatshirt
560 - 336 = 224
Answer:
The volume of the solid = π²
Step-by-step explanation:
As per the given data of the questions,
The diameter of each disk is
D = 2 sin(x) - 2 cos(x)
So its radius is
R = sin(x) - cos(x).
The area of each disk is

![= \pi \times [sin^{2}(x) - 2 sin(x) cos(x) + cos^{2}(x)]](https://tex.z-dn.net/?f=%3D%20%5Cpi%20%5Ctimes%20%5Bsin%5E%7B2%7D%28x%29%20-%202%20sin%28x%29%20cos%28x%29%20%2B%20cos%5E%7B2%7D%28x%29%5D)
![= \pi[1-2sin(x)cos(x)]](https://tex.z-dn.net/?f=%3D%20%5Cpi%5B1-2sin%28x%29cos%28x%29%5D)
![= \pi[1-sin(2x)]](https://tex.z-dn.net/?f=%3D%20%5Cpi%5B1-sin%282x%29%5D)
Now,
Integrate from
, we get volume:
![V=\int_{\frac{\pi}{4}}^{\frac{5\pi}{4}} \pi[1-sin(2x)]dx](https://tex.z-dn.net/?f=V%3D%5Cint_%7B%5Cfrac%7B%5Cpi%7D%7B4%7D%7D%5E%7B%5Cfrac%7B5%5Cpi%7D%7B4%7D%7D%20%5Cpi%5B1-sin%282x%29%5Ddx)
After integrate without limit we get
![V=\pi[x+\frac{cos2x}{2}]](https://tex.z-dn.net/?f=V%3D%5Cpi%5Bx%2B%5Cfrac%7Bcos2x%7D%7B2%7D%5D)
Now after putting the limit, we get
V = π²
Hence, the required volume of the solid = π²
Answer:
The age of pluto is:
5,560,000,000 years old = 5.56 × 10⁹ years old
x = 5.56
y = power of 9
Step-by-step explanation:
Pluto is 5,560,000,000 years old. Estimate the age of Pluto by writing it in the form of x×10y years, where x and y are single-digit numbers.
We write this in standard form or scientific notation.
5,560,000,000 years old = 5.56 × 10⁹ years old
x = 5.56
y = power of 9
Sum/difference:
Let

This means that

Now, assume that
is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that
was rational, which proves that the sum/difference of the two given terms was irrational
Multiplication/division:
The logic is actually the same: if we multiply the two terms we get

if again we assume x to be rational, we have

But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.