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ahrayia [7]
3 years ago
8

Factor completely and check mentally. 12a^2b^2-144ab

Mathematics
1 answer:
Nikitich [7]3 years ago
3 0
12ab(ab-12) is the factored form of this equation.
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Suppose you are asked to find the area of a rectangle that is 2.1-cm wide by 5.6-cm long. Your calculator answer would be 11.76
IRINA_888 [86]

Answer:

The area of the rectangle is 12 cm² (to two significant figures)

Step-by-step explanation:

To determine the area of a rectangle that is 2.1-cm wide by 5.6-cm long,

The area of a rectangle is given by

Area = l × w

where l is the length

and w is the width

From the question,

l = 5.6 cm

and w = 2.1 cm

Hence, Area of the given rectangle will be

Area = 5.6 cm × 2.1 cm

Area = 11.76 cm²

Now, we will convert the answer to two significant figures

Then,

Area = 12 cm²

Hence, the area of the rectangle is 12 cm² (to two significant figures)

3 0
3 years ago
Pls help me very urgently needed
Kisachek [45]
Ratio is 7:9
add the ratio it becomes 16
272 members divided by 16
that makes it 17 per one ratio
women ratio is 9
17x9 is 153
i=153 women in the sports club

same thing with ii except it’s divided by 7
91/7 is 13
which means 13 per ratio
there are 9 ratios of women
9x13=117
ii=117 women in a sports club with 91 men with a ratio of 7:9
4 0
3 years ago
Answer this question pls!!
Dvinal [7]

Answer:

3.5

Step-by-step explanation:

5 0
3 years ago
I really am confused on how to write a proof.
kvasek [131]

Since ABCD is a parallelogram, the opposite sides will be parallel and equal,

\begin{gathered} AB=CD \\ BC=AD \end{gathered}

Consider that AC acts as a transversal to the parallel lines AB and CD, so we can write,

\begin{gathered} \angle CAD=\angle ACB\text{ (Alternate Interior Angles)} \\ BC=AD\text{ (Opposite sides of parallelogram)} \\ \angle ADB=\angle CBD\text{ (Alternate Interior Angles)} \end{gathered}

So by the ASA criteria, the triangle AED is congruent to the triangle CEB,

Then the corresponding parts of the triangles will be equal,

\begin{gathered} AE=CE \\ BE=DE \end{gathered}

Hence Proved.

8 0
1 year ago
With a short time remaining in the​ day, a delivery driver has time to make deliveries at 4 locations among the 7 locations rema
omeli [17]

Answer:

35 different routes

Step-by-step explanation:

The problem of how many different routes are possible if a driver wants to make deliveries at 4 locations among 7 locations is a combination problem.

Combination problems are usually selection problems, of all or part of a set of options, without considering the order in which options are selected.

The number of combinations of n objects taken r at a time is: ⁿCᵣ

So, the number of ways the driver can make deliveries at 4 locations out of 7 locations of given by

⁷C₄ = 35 different ways.

Hence, 35 different routes are possible to make deliveries at 4 locations out of 7 locations.

Hope this Helps!!!

3 0
3 years ago
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