Answer:

Step-by-step explanation:
The variable w is equivalent to y, and the variable z is equivalent to x.


1)
=> <span>m∠2 = 2x +13
=> </span><span><span>m∠1 = </span> 4x - 1
Since YP angle bisector the angles with be equal to each other,
</span>
m∠1 = <span>m∠2
2x + 13 = 4x - 1
2x - 4x = -1 -13
-2x = -14
x = 7
</span>
All other questions are to be done in that way, don't be lazy :P
It's C I looked it up for you I promise it's right :D
Answer:
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Answer:
Step-by-step explanation:
This question is asking us to find where sin(2x + 30) has a sin of 1. If you look at the unit circle, 90 degrees has a sin of 1. Mathematically, it will be solved like this (begin by taking the inverse sin of both sides):
![sin^{-1}[sin(2x+30)]=sin^{-1}(1)](https://tex.z-dn.net/?f=sin%5E%7B-1%7D%5Bsin%282x%2B30%29%5D%3Dsin%5E%7B-1%7D%281%29)
On the left, the inverse sin "undoes" or cancels the sin, leaving us with
2x + 30 = sin⁻¹(1)
The right side is asking us what angle has a sin of 1, which is 90. Sub that into the right side:
2x + 30 = 90 and
2x = 60 so
x = 30
You're welcome!