Using the z-distribution, the 99% confidence interval to estimate the population proportion is: (0.2364, 0.4836).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, we have a 99% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 2.575.
The estimate and the sample size are given by:
.
Then the bounds of the interval are:
The 99% confidence interval to estimate the population proportion is: (0.2364, 0.4836).
More can be learned about the z-distribution at brainly.com/question/25890103
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First if there are 47/80 we have to estimate like 47 is 50 and 82 is 80
First, 47.7-45 to get price increase by tax for I which is 2.7. next divide 2.7 by 45 and multiply that by 100 to get a sales tax of 6%. Next 37.7-35 is once again 2.7. divide 2.7/35 and multiply times 100 to get a sales tax of 7.7 for T. T=7.7% and I=6% so since 7.7>6, therefore Tennessee has a greater sales tax then Iowa
Answer:
its the first one brsinlest plz
Step-by-step explanation:
Could you resend the picture it isn't clear?