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3 years ago

Winston plans to hire a moving company to help him

Mathematics

1 answer:

Rina8888 [55]3 years ago

8 0

The maximum whole number of hours is 4 hours.

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~Please help as soon as possible~

Setler79 [48]

60/40 =5

40*5=200

Answer For 1 is 200

35/10=3.5

20*3.5=70

Answer For 2 is 70 Pounds

85/40=2.125

2.125*600

1275

Answer For 3 is 1275

5 0

3 years ago

Read 2 more answers

How can I figure out this math problem: Stanley ran a 5 kilometer race in 30 minutes. What was his speed in kilometers per hour?

stiv31 [10]

Since the question is asking for the time units to be in hours, you want to convert 30 minutes to an hour; 0.5

We’re able to use the basic motion formula for velocity to work out this question.

Velocity = distance / time
Velocity = 5 / 0.5
Velocity = 10km/h

Therefore, Stanley’s average speed was 10 kilometres per hour. :)

3 0

2 years ago

a fruit salad contains 20 different pieces of fruit. there are 3 pieces of apple, 8 pieces of watermelon, 7 pieces of banana, an

Neko [114]

There are 2 oranges, if that’s what the question was?

8 0

2 years ago

Read 2 more answers

The sales of a grocery store had an average of $8,000 per day. The store introduced several advertising campaigns in order to in

oksano4ka [1.4K]

Answer:

Null hypothesis: $\mu \leq 8000$

Alternative hypothesis: $\mu > 8000$

$z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2$

$p_v =P(Z>2)=0.0228$

Step-by-step explanation:

1) Data given and notation

$\bar X=8300$ represent the sample mean

$\sigma=1200$ represent the population standard deviation

$n=64$ sample size

$\mu_o =800$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 8000, the system of hypothesis are :

Null hypothesis: $\mu \leq 8000$

Alternative hypothesis: $\mu > 8000$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2$

4) P-value

Since is a one-side upper test the p value would given by:

$p_v =P(Z>2)=0.0228$

5) Conclusion

If we compare the p value and the significance level assumed, for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly higher than $8000.

4 0

2 years ago

Plz hurry!!!! thank you!!!!

tatyana61 [14]

Step-by-step explanation:

Since SP=TR, the differnce of PR and ST 24-15 divided by 2 is the length of PD (4.5)

Try to understand the rest from the attached picture

3 0

3 years ago