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Alchen [17]
3 years ago
11

In which quadrants is the ordinate positive? a)I and II b)II and III c)I and IV

Mathematics
1 answer:
nasty-shy [4]3 years ago
8 0
The ordinate is the y element in an ordered pair in a Cartesian coordinate system. The quadrants in which the ordinates are positive should be at quadrants I and II. Therefore, the correct answer from the choices listed above is option A.
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What reasons might venita give for saying that the 1916 coin is most likely in her bag? Sherelle claims that she has 26 which is closer to 16 hence her chances are more.

Step-by-step explanation:

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3 years ago
Which pack of cookies can be shared 15,11,19,23?​
lubasha [3.4K]
The answers 15.

Explanation: you can’t evenly divide the other option choices
3 0
3 years ago
A steel safe with mass 2200 kg falls onto concrete. Just
Virty [35]

The kinetic energy of the safe increases the force exerted by the concrete

to several times the weight of the safe.

  • The magnitude of the force exerted on the safe by the concrete on the is approximately \underline{29.\overline 3 \, \mathrm{MN}}
  • The concrete exerts a <u>force</u> that is approximately <u>1,359.16 times the weight of the safe</u>.

Reasons:

First part

The mass of the steel safe, m = 2,200 kg

Velocity of the safe just before it hits the concrete, v = 40 m/s

The amount by which the safe was compressed, d = 0.06 m

The kinetic energy, K.E., of the safe just before it hits the round is therefore;

\displaystyle K.E. = \mathbf{\frac{1}{2} \cdot m \cdot v^2}

\displaystyle K.E._{safe} = \frac{1}{2} \times 2,200 \times 40^2 = 1,760,000 \ Joules

Work done by concrete, W = Force, F × Distance, d

  • \displaystyle Force, \, F = \mathbf{\frac{Work, \, W}{Distance, \, d}}

By the law of conservation of energy, we have;

The work done by the concrete, W = The kinetic energy, K.E. given by the safe

W = K.E. = 1,760,000 J

The effect of the work = The change in the height of the safe

Therefore;

The distance, <em>d</em>, over which the force of the concrete is exerted = The change in the height of the safe = 0.06 m

d = 0.06 m

Therefore;

\displaystyle The \ force \ of \ the \ concrete, \, F = \frac{1,760,000\, J}{0.06 \, m} = 29,333,333. \overline 3 \, N = 29.\overline 3 \ MN

  • The force of the concrete on the safe = \underline{29.\overline 3 \ MN}

Second part:

The gravitational force of the Earth on the safe, W = The weight of the safe

W = Mass, m × Acceleration due to gravity, g

W = 2,200 kg × 9.81 m/s² ≈ 21,582 N

The ratio of the force exerted by the concrete to the weight of the safe is found as follows;

\displaystyle Ratio \ of \ forces = \frac{29.\overline 3 \times 10^6 \, N}{21,582 \, N} = \frac{4,000,000}{2,943} \approx \mathbf{1359.16}

  • The <u>force</u> exerted by the concrete is approximately <u>1,359.16 times the weight of the safe</u>.

Learn more here:

brainly.com/question/21060171

5 0
3 years ago
Please answer this question!
mina [271]

Answer:

x=32

Step-by-step explanation:

UVT is 90 degrees and a circle is 180 degrees so...

(180-90)-55=35

35-3=32

Answer: x=32

8 0
3 years ago
I’m not sure on this one please need help on this
LuckyWell [14K]

Answer:

c

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
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