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3 years ago

In which quadrants is the ordinate positive? a)I and II b)II and III c)I and IV

1 answer:

8 0

The ordinate is the y element in an ordered pair in a Cartesian coordinate system. The quadrants in which the ordinates are positive should be at quadrants I and II. Therefore, the correct answer from the choices listed above is option A.

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What is x- and y- intercept of -7x + 2y= 14

Novosadov [1.4K]

The y-intercept is (0,7) and the x-intercept is (-2,0).

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3 years ago

Determine the equations of the vertical and horizontal asymptotes if any for h(x)=(x+1)^2/x^2-1

shepuryov [24]

ANSWER

Vertical asymptote:

x=1

Horizontal asymptote:

y=1

EXPLANATION

The given rational function is

$h(x) = \frac{ {(x + 1)}^{2} }{ {x}^{2} - 1 }$

$h(x) = \frac{ {(x + 1)}^{2} }{ ({x} - 1)(x + 1)}$

$h(x) = \frac{ (x + 1)(x + 1) }{ ({x} - 1)(x + 1)}$

$h(x) = \frac{ x + 1}{ {x} - 1}$

The vertical asymptote occurs at

${x} - 1 = 0$

$x = 1$

The vertical asymptotes is x=1

The degree of the numerator is the same as the degree of the denominator.

The horizontal asymptote of such rational function is found by expressing the coefficient of the leading term in the numerator over that of the denominator.

$y = \frac{1}{1}$

y=1

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3 years ago

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3 years ago

In ΔPQR, \overline{PR} PR is extended through point R to point S, \text{m}\angle QRS = (4x-15)^{\circ}m∠QRS=(4x−15) ∘ , \text{m}

mixas84 [53]

Answer:

Step-by-step explanation:

Notice that, the angle QRS is external to the triangle and adjacent to the angle PRQ. According to the theorem of a external/adjacent angle, we have: m∠QRS = m∠PQR + m∠RPQ, where PQR and RPQ are internal angles.

From the hypothesis, we have:

m∠QRS =(10x−12)∘(10x−12)

m∠PQR = (3x+20)∘(3x+20)

m∠RPQ=(3x−8)∘(3x−8)

Using the first equation and replacing the hypothesis:

m∠QRS = m∠PQR + m∠RPQ

(10x−12)∘(10x−12) = (3x+20)∘(3x+20) + (3x−8)∘(3x−8)

Multiplying and applying the remarkable identity:

Then, we use a calculator to find the roots, which are:

In this case, we will see what root is the right one.

Now, we replace it into m∠QRS =(10x−12)∘(10x−12), because we need to find m∠QRS.

m∠QRS =(10x−12)∘(10x−12) = (10(4.7) - 12) (10(4.7) - 12) = (35) (35) = 1225

Step-by-step explanation:

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3 years ago

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Domain of the function

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