Product is 5x4 so 20+2 the answer is 22
Answer: the probability that a person who tested positive actually has TB is 0.64
Step-by-step explanation:
lets say
T : has tuberculosis
+ : test results +ve
- : test result is -ve
so given that
P(+ITc) = 0.008
P(-ITc) = 0.15
P(T) = 50/3000 = 1/60
P(Tc) = 1 - P(T) = 1 - 1/60 = 59/60
Now required probability
= P(TI+)
P(T∩+) / P(+)
= P(T) × P(+IT) / [[P(T) × P(+IT)] + [(P(Tc) × P(+ITc)]
= P(T) × {1-P(-IT)] / [[P(T) × [1-P(-IT)] + [(P(Tc) × P(+ITc)]
WE SUBSTITUTE
= { 1/60 × (1-0.15) } / [1/60 × (1 - 0.15)] + [(59/60) × 0.008]
= (0.0167 × 0.85) / [(0.0167 × 0.85) + (0.9833 × 0.008)]
= 0.01417 / 0.02206
= 0.6423 ≈ 0.64
∴ the probability that a person who tested positive actually has TB is 0.64
The answer for that question is Angle bisectors
125.6
Area of a circle = πr^2
Area of circle 1 = 3.14 × 11 × 11
=379.94cm^2
Area of circle 2= 3.14 × 9 ×9
=254.64cm^2
Area of a shaded region
=379.94cm^2 - 254.64cm^2
=125.60cm^2
