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Anit [1.1K]
3 years ago
13

I need to find each angle. Please help!!

Mathematics
1 answer:
vredina [299]3 years ago
8 0
The sum of internal angles of a triangle is 180°, so:
3x+2x+50+x+46=180
6x=84
x=14

angle a = 3*14=42
angle b = 2*14+50=78
angle c = 14+46=60
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X-y=6<br> 2x-3z=16<br> 2y+z=4<br><br> Solve the systems of equations.
Neko [114]

Answer:

Given System of equation:

x-y =6                                  .....,[1]

2x-3z = 16                           ......[2]  

2y+z = 4                              .......[3]

Rewrite the equation [1] as

y = x - 6                                .......[4]

Substitute the value of [4] in [3], we get

2(x-6)+z = 4

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then, we have

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Add 12 to both sides of an equation:

2x-12+z+12=4+12

Simplify:

2x +z = 16                         .......[5]

On substituting equation [2] in [5] we get;

2x+z=2x -3z

or

z = -3z

Add 3z both sides of an equation:

z+3z = -3z+3z

4z = 0

Simplify:

z = 0

Substitute the value of z = 0 in [2] to solve for x;

2x-3(0) = 16

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2x = 16

Divide by 2 both sides of an equation:

\frac{2x}{2} =\frac{16}{2}

Simplify:

x= 8

Substitute the value of x =8 in equation [4] to solve for y;

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y = 2

Therefore, the solution for the given system of equation is;  x = 8 , y = 2 and z =0

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