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BaLLatris [955]
3 years ago
8

Please help :( real quick

Mathematics
1 answer:
NARA [144]3 years ago
3 0
AOB and DOE. Supplementary angels are two angles that add up to 180 degrees. I just eyeballed it, but it should be correct.
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What is the slope of a line that is perpendicular to the line y = 8x + 5?
Pavel [41]

The slope of a line that is perpendicular to the line y = 8x + 5 will be -1/8.

<h3>What is the slope of perpendicular lines?</h3>

Suppose that first straight line has slope 's'

Let another straight line be perpendicular to this first line.

Let its slope be 'a'

Then due to them being perpendicular, they have their slopes' multiplication as -1

or

s x a = -1

s = -1/ a

Slope of line y = 8x + 5

s = 8

The slope of a line that is perpendicular to the line y = 8x + 5

8 x a = -1

a = -1/8

Thus, the slope is -1/8.

Learn more about slope here:

brainly.com/question/2503591

#SPJ1

8 0
2 years ago
Which is a unit rate?<br> 3:5 2:6 4:7 5:1
kogti [31]

Step-by-step explanation:

all......................

5 0
3 years ago
Find the slope/rate of change of the line on the graph.
ohaa [14]

Answer:

y=-1

From where the line crosses the y axis, it goes up 1 and over 1 from each plane although its moving to the left from 0 every time. This means the slope is negative.

In the equation y=mx+b, b is the y intercept and m is the slope

plugin the info and you get y=-1x+0 or

y=-1x

Step-by-step explanation:

5 0
3 years ago
Dillon can buy a fixed-rate bond with a 4% coupon, a $10,000 principal, and five years left to maturity or a TIPS with the same
Keith_Richards [23]
<span>3 Both yields are roughly equivalent.</span>
7 0
4 years ago
Read 2 more answers
Please help me w the answer
evablogger [386]

Answer:

\frac{2(x-6)(x-10)}{(x-4)(x-5)}

Step-by-step explanation:

In essence, one needs to work their way backwards to solve this problem. Use the information to construct the function.

The function has verticle asymptotes at (x = 4) and (x = 5). This means that the denominator must have (x - 4) and (x - 5) in it. This is because a verticle asymptote indicates that the function cannot have a value at these points, the function jumps at these points. This is because the denominator of a fraction cannot be (0), the values (x - 4) and (x - 5) ensure this. Since if (x) equals (4) or (5) in this situation, the denominator would be (0) because of the zero product property (this states that any number times zero equals zero). So far we have assembled the function as the following:

\frac{()}{(x-4)(x-5)}

The function has x-intercepts at (6, 0), and (0, 10). This means that the numerator must equal (0) when (x) is (6) or (10). Using similar logic that was applied to find the denominator, one can conclude that the numerator must be ((x - 6)(x-10)). Now one has this much of the function assembled

\frac{(x-6)(x-10)}{(x-4)(x-5)}

Finally one has to include the y-intercept of (0, 120). Currently, the y-intercept is (60). This is found by multiplying the constants together. (6 * 10) equals (60). One has to multiply this by (2) to get (120). Therefore, one must multiply the numerator by (2) in order to make the y-intercept (120). Thus the final function is the following:

\frac{2(x-6)(x-10)}{(x-4)(x-5)}

6 0
3 years ago
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