Ask question

Ask question

All categories

4 years ago

6

A cinema is selling movie tickets for adults and children. If one person buys 3 adult tickets and 10 child tickets and spends $1

75, and another person buys 6 adult tickets and 7 child tickets and spends $220, how much does each type of movie ticket cost?

1 answer:

DaniilM [7]4 years ago

4 0

The adult ticket cost $25 while the child one cost $10.

You might be interested in

You can use a linear model to represent the relationship between the hours worked h and the money earned m. When h = 0, then m =

Dennis_Churaev [7]

You can use a proportion to get the answer $162.50

$39/6hours = X/25hours (cross multiply)
x=$162.50

7 0

4 years ago

Colton wrote a ratio comparing the number of sports video games that he owns to the number of driving video games that he owns a

Ede4ka [16]

4 to 3
Explanation:

Putting a “to” In-between two numbers is another way of saying 4:3

4 0

3 years ago

Read 2 more answers

Please help!! I’m not sure how to answer this question!!

nlexa [21]

<h3>Answer: 9V</h3>

=============================================================

Reason:

The volume expression of a cone with radius r and height h is

$\frac{1}{3}\pi*r^2*h$

Let's plug in the given height h = 12 and we'd get

$\frac{1}{3}\pi*r^2*h\\\\\frac{1}{3}\pi*r^2*12\\\\\left(\frac{1}{3}*12\right)\pi*r^2\\\\4\pi*r^2\\\\$

This is the volume of the first cone. We're told the first cone has a volume of V, so we can say $V = 4\pi r^2$

We can't find the actual numeric volume because we don't know what value replaces r. So we leave it as is.

The second cone has the same height (h = 12) but the radius is now 3 times in size. Instead of r, we use 3r

Replace every copy of r with 3r. Then simplify

$4\pi*r^2\\\\4\pi*(3r)^2\\\\4\pi*9r^2\\\\9(4\pi r^2)\\\\9V\\\\$

The radius tripled which results in a volume that's 9 times bigger.

3 0

2 years ago

Eir answers<br> Find the product. Draw a model.<br> 1.<br> eeded)

diamong [38]

I need more information about this question

4 0

3 years ago

PLEASEEEEE HEEEEEELPPPPPPPPPPPPPPP

dezoksy [38]

1. Let m∠ABK=x°. Since line BK bisects ∠ABD, then

m∠ABK=m∠KBD=x°.

Also m∠ABD=m∠ABK+m∠KBD=2x°.

2. The diagonal BD of rhombus ABCD bisects ∠ABC, then

m∠ABD=m∠DBC=2x°.

This gives you that

m∠ABC=4x°.

3. Angles A and B are supplementary, so

m∠A+m∠B=180°,

m∠A=180°-4x°.

4. Consider triangle ABK. The sum of the measures of interior angles in triangle is always 180°, thus

m∠A+m∠ABK+m∠AKB=180°,

m∠AKB=180°-x°-(180°-4x°),

m∠AKB=3x°=3m∠ABK.

8 0

3 years ago

Read 2 more answers