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natka813 [3]
2 years ago
11

Please help!! I’m not sure how to answer this question!!

Mathematics
1 answer:
nlexa [21]2 years ago
3 0
<h3>Answer:  9V</h3>

=============================================================

Reason:

The volume expression of a cone with radius r and height h is

\frac{1}{3}\pi*r^2*h

Let's plug in the given height h = 12 and we'd get

\frac{1}{3}\pi*r^2*h\\\\\frac{1}{3}\pi*r^2*12\\\\\left(\frac{1}{3}*12\right)\pi*r^2\\\\4\pi*r^2\\\\

This is the volume of the first cone. We're told the first cone has a volume of V, so we can say V = 4\pi r^2

We can't find the actual numeric volume because we don't know what value replaces r. So we leave it as is.

The second cone has the same height (h = 12) but the radius is now 3 times in size. Instead of r, we use 3r

Replace every copy of r with 3r. Then simplify

4\pi*r^2\\\\4\pi*(3r)^2\\\\4\pi*9r^2\\\\9(4\pi r^2)\\\\9V\\\\

The radius tripled which results in a volume that's 9 times bigger.

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no because she turned it only 90 degrees not 180.

180 would be a mirror reflection

6 0
3 years ago
HELPP ASAPPP
Softa [21]

Answer:

3/8

Step-by-step explanation:

3/4*1/2=3/8

3/8*1=3/8

*=multiply

3 0
3 years ago
How do you convert 60 miles per hour is how many feet per second? can iny one help
DiKsa [7]
That's two questions.

The answer to the second question is:  Yes.

The answer to the first question is:

Multiply 60 miles per hour by ' 1 ' a few times.  Use fractions that have
the same thing on top and bottom, since those are always equal to ' 1 '.
Then cancel units if the same unit is on the top and the bottom.
Here's how it goes:

(60 mi/hr) x (5280 ft/mile) x (1hr/3600 sec) = (60 x 5280 / 3600) ft/sec = <u>88 ft/sec</u>

8 0
3 years ago
Find the probability of spinning an A 3 times
Dima020 [189]
If the probability of spinning an A once is 1/12, then the probability of spinning an A 3 times is 3 × 1/12.

3 × 1/12 = 3/36

Simplify

3/36 = 1/12
6 0
3 years ago
Consider a fictitious company, Teslala, that produces a single type of electronic vehicle, Model Z. The demand for Model Z depen
grin007 [14]

The ratio X/Y for the fictitious company, Teslala, that produces a single type of electronic vehicle, Model Z is 10/pY.

<h3>What is a mathematical model?</h3>

A mathematical model is the model which is used to explain the any system, the effect of the components by study and estimate the functions of systems.

Consider a fictitious company, Teslala, that produces a single type of electronic vehicle, Model Z.

The demand for Model Z depends on the gasoline price (q) because customers tend to purchase an electronic vehicle as a substitute for vehicles that run on gasoline when the gasoline price increases.

The demand for Model Z is estimated as

D(p) = 180 + 10q - 4p

Here, <em>p</em> is the price of Model Z.

Consider the following two statements:

  • 1. When the average gasoline price q increases by $1, the revenue-maximizing price p" increases by $X.

D(p) = 180 + 10q - 4p\\D(p) = 180 + 10(q+1) - 4(p+X)

  • 2. When the average gasoline price q increases by $1, the demand at the revenue-maximizing price (i.e., D(p*)) increases by a factor of Y.

D(p)+Y = 180 + 10q - 4p\\(D(p)+Y) = 180 + 10(q+1) - 4(p+X)\\Y= 180 + 10(q+1) - 4(p+X)-D(p)\\

Put the value of demand at the revenue-maximizing price as,

Y= 180 + 10(q+1) - 4(p+X)-(180 + 10q - 4p)\\Y= 180 + 10q+10 - 4p-pX-180 - 10q + 4p\\Y= 10 -pX\\1=\dfrac{10}{Y}-\dfrac{pX}{Y}\\\dfrac{10}{Y}=\dfrac{pX}{Y}\\\dfrac{10}{pY}=\dfrac{X}{Y}

Thus, the ratio X/Y for the fictitious company, Teslala, that produces a single type of electronic vehicle, Model Z is 10/pY.

Learn more about the mathematical model here;

brainly.com/question/4960142

#SPJ1

5 0
2 years ago
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