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Vanyuwa [196]
3 years ago
7

Assume that you have a binomial experiment with p = 0.5 and a sample size of 100. the expected value of this distribution is

Mathematics
1 answer:
Alex73 [517]3 years ago
7 0
N=100, p=0.5
expected value = mean = np =50
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Seven more than the quotient of a number and 5 is equal 2
faust18 [17]

Answer:

-20

Step-by-step explanation:

n/4 + 7 = 2

n/4 = -5

n = -20

8 0
3 years ago
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On a winter morning, the temperature before sunrise was -10℉. The temperature then rose by 1℉ each hour for 7 hours before dropp
Artemon [7]

Answer:

The temperature after 10 hours is -9 ºF.

Step-by-step explanation:

This statement can be translated mathematically as follows. The temperature after 10 hours from sunrise is:

T = -10\,^{\circ}F + \left(1\,\frac{^{\circ}F}{h} \right)\cdot (7\,h)+ \left(-2\,\frac{^{\circ}F}{h} \right)\cdot (3\,h)

T = -9\,^{\circ}F

The temperature after 10 hours is -9 ºF.

6 0
3 years ago
Due to client growth, Dr. Smith must increase his amount of kennel space from
Tomtit [17]

Answer:

14

Step-by-step explanation:

25-11 = 14

4 0
3 years ago
Help me please???<br> I don’t know how to get started!
Sliva [168]

A differentiable function f(x) is increasing on an open interval (a,b) if f'(x)>0 for all a, and decreasing if f'(x). For this problem, you then need to compute the derivative:

f(x)=x^2\ln x\implies f'(x)=2x\ln x+x=(2\ln x+1)x

then solve for f'(x)=0:

(2\ln x+1)x=0\implies x=0\text{ or }x=e^{-1/2}

We can ignore x=0 because x^2\ln x is defined only for x>0. So we have two intervals to consider, (0,e^{-1/2}) and (e^{-1/2},\infty). All we need to do is pick any value from either interval and check the sign of the derivative f'(x). Since e^{-1/2}\approx0.606, from the first interval we can take x=\dfrac12, and from the second we can pick x=1.

f'\left(\dfrac12\right)\approx-0.193

f'(1)=1>0

The above indicates that f(x) is decreasing on the first interval (0,e^{-1/2}), and increasing on the second interval (e^{-1/2},\infty).

For part (b), we use the info from above as part of the first derivative test for extrema. We have one critical point at x=e^{-1/2}, and we know how f(x) behaves to either side of this point; f(x) decreases to left of it, and increases to the right. This pattern is indicative of a minimum occurring at x=e^{-1/2}, and we find that f(x) has the (local) minimum value of f(e^{-1/2})=-\dfrac1{2e}\approx-0.184.

8 0
3 years ago
A school system is reducing the amount of dumpster loads of tosh removed each week. In week 5, there were 60 dumpster loads of w
Degger [83]
(5,60)(10,40)
slope = (40 - 60) / (10 - 5) = - 20/5 = -4

y = mx + b
slope(m) = -4
(5,60)...x = 5 and y = 60
now we sub and find b, the y int
60 = -4(5) + b
60 = -20 + b
60 + 20 = b
80 = b

equation is : y = -4x + 80
function form : f(x) = -4x + 80...where x = number of weeks and f(x) = loads of waste removed 

7 0
3 years ago
Read 2 more answers
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