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Aleonysh [2.5K]

3 years ago

8

suppose sin(theta)=2/5, use the trig identity sin^2(theta)+cos^2(theta)=1 and the trig identity tan(theta)=sin(theta)/cos(theta)

fine tan(theta) in quadrant I. round to ten-thousandth.

1 answer:

IRISSAK [1]3 years ago

4 0

Answer:

tanθ ≅ 0.4364

Step-by-step explanation:

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Kamila [148]

Answer: $509

Step-by-step explanation:

Given : Gabe is getting married in three years and wants to save $20,000 for his wedding. He opens an account earning 6% interest, compounded monthly.

According to the given description, we have

A= $20,000 , r= 6%=0.06 , t= 3 years , n= 12 [1 yearn = 12 months]

Formula to find Periodic monthly deposit :-

$P=\dfrac{A\left(\dfrac{r}{n}\right)}{\left(1+\dfrac{r}{n}\right)^{\left(n\cdot t\right)}-1}$

Substitute given values in the above formula , we get

$P=\dfrac{20000\left(\dfrac{0.06}{12}\right)}{\left(1+\dfrac{0.06}{12}\right)^{\left(3\cdot12\right)}-1}\\\\=\dfrac{100}{1.19668052482-1}\\\\=\dfrac{100}{0.19668052482}=508.438749031\approx509$

Hence, the periodic monthly deposit (payment) needed to achieve a balance of $20,000 after three years= $509.

8 0

3 years ago

I need Help !!!!!!!!!!!!!!!!!!!!!!!!

Alla [95]

Answer: x < - 5 or x ≥ 4

Step-by-step explanation:

3 0

3 years ago

Please simplify the expression.

natka813 [3]

The answer would be C in my opinion

8 0

3 years ago

Which of the following choices simplified the expression:

forsale [732]

<h2>Hello!</h2>

The answer is:

The correct option is the second option:

$\frac{5}{2},\frac{-1}{2}$

<h2>Why?</h2>

We are given the following expression:

$\frac{2+-\sqrt{9}}{2}$

Now, solving we have:

First solution:

$\frac{2+\sqrt{9}}{2}=\frac{2+3}{3}=\frac{5}{2}$

Second solution:

$\frac{2-\sqrt{9}}{2}=\frac{2-3}{3}=\frac{-1}{2}$

Hence, we have that the correct option is the second option:

$\frac{5}{2},\frac{-1}{2}$

Have a nice day!

5 0

3 years ago

Read 2 more answers

Please help I did not get what I was supposed to do

Sladkaya [172]

Answer:

See below

Step-by-step explanation:

$\sqrt[3]{49} = 3.65930571002 \approx3.66 \\ \\ so \: \sqrt[3]{49} should \: lie \: at \: 3.6 \: which \: \\ fall \: between \: 3 \: and \: 4.$

Actually Lin did a mistake, she obtained square root and not cube root.

8 0

2 years ago

Read 2 more answers