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Aleonysh [2.5K]

3 years ago

8

suppose sin(theta)=2/5, use the trig identity sin^2(theta)+cos^2(theta)=1 and the trig identity tan(theta)=sin(theta)/cos(theta)

fine tan(theta) in quadrant I. round to ten-thousandth.

1 answer:

IRISSAK [1]3 years ago

4 0

Answer:

tanθ ≅ 0.4364

Step-by-step explanation:

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A dog uses 30 lbs of dog food per day. How many pounds are used in a year?

Ludmilka [50]

To solve this we would do 30×365

We would do this because each day the dog 30lbs

So we have the equation y=30x
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In a year there are 365 days typically, so we do 30×365

30×365=10,950

In one year 10,950 lbs of dog food are used

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Five years ago, Benjamin invested in Parchar Special Effects. He purchased four par value $1,000 bonds from Parchar Special Effe

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Answer:

Five years ago, Benjamin invested in Parchar Special Effects. He purchased four par value $1,000 bonds from Parchar Special Effects at a market rate of 96.230. Each bond had an interest rate of 7.2%. Benjamin also purchased 200 shares of stock in the same company, each of which cost $19.08 and had a yearly dividend of $2.04. Today, bonds from Parchar Special Effects have a market rate of 104.595, and stock in Parchar Special Effects costs $22.62. If Benjamin liquidates his portfolio and sells all of his investments, which aspect of his investment will have yielded him a greater total profit, and how much greater is it?

Step-by-step explanation:

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4 years ago

A company plans to build a wheelchair ramp with the following

Liono4ka [1.6K]

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Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

The 80% confidence interval for the the population mean nitrate concentration is (0.144, 0.186).

Critical value t=1.318

Step-by-step explanation:

We have to calculate a 80% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=0.165.

The sample size is N=25.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{0.078}{\sqrt{25}}=\dfrac{0.078}{5}=0.016$

The degrees of freedom for this sample size are:

$df=n-1=25-1=24$

The t-value for a 80% confidence interval and 24 degrees of freedom is t=1.318.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_M=1.318 \cdot 0.016=0.021$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 0.165-0.021=0.144\\\\UL=M+t \cdot s_M = 0.165+0.021=0.186$

The 80% confidence interval for the population mean nitrate concentration is (0.144, 0.186).

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4 years ago