Answer:
The angle between the given vectors u and v is ![\theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]](https://tex.z-dn.net/?f=%5Ctheta%3Dcos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B3%7D%7B%5Csqrt%7B10%7D%7D%5Cright%5D)
Step-by-step explanation:
Given vectors are 
and 
Now compute the dot product of u and v:
Now find the magnitude of u and v:
To find the angle between the given vectors
![\theta=cos^{-1}\left[\frac{\overrightarrow{u}.\overrightarrow{v}}{|\overrightarrow{u}|\overrightarrow{v}|}\right]](https://tex.z-dn.net/?f=%5Ctheta%3Dcos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B%5Coverrightarrow%7Bu%7D.%5Coverrightarrow%7Bv%7D%7D%7B%7C%5Coverrightarrow%7Bu%7D%7C%5Coverrightarrow%7Bv%7D%7C%7D%5Cright%5D)
![=cos^{-1}\left[\frac{15}{5\times \sqrt{10}}\right]](https://tex.z-dn.net/?f=%3Dcos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B15%7D%7B5%5Ctimes%20%5Csqrt%7B10%7D%7D%5Cright%5D)
Therefore the angle between the vectors u and v is
The equation to calculate the average rate of change is: y/x
y = f(x2) - f(x1)x = x2 - x1
x1: 1 (The smaller x value. It can be any number)x2: 2 (The larger x value. It also can be any number)f(x1): The value when you plug x1 into the function.f(x2): The value when you plug x2 into the function.
If we know this, the variables for this problem are assuming the function is 10(5.5)^x:
x2: 2x1: 1f(x2): 10(5.5)^(2) = 302.5f(x1): 10(5.5)^(1)= 55
This means:y = 302.5 - 55 = 247.5x = 2 - 1 = 1
Remember: the equation for avg rate of change is y/x
So, our average rate of change for the function on the interval [1,2] is 247.5 (y/x = 247.5/1)
Umm could you give me the whole question? Maybe I could answer it
Answer:
ab² - a²b
Step-by-step explanation:
a²b⁴ - b²a⁴ can be factored as a²b²(b² - a²) which becomes a²b²(b + a)(b - a). Since the numerator and denominator both have (a + b) and ab the final answer is ab(b - a) = ab² - a²b.
