Answer:
4.


5.


Step-by-step explanation:
The sides of a (30 - 60 - 90) triangle follow the following proportion,

Where (a) is the side opposite the (30) degree angle, (
) is the side opposite the (60) degree angle, and (2a) is the side opposite the (90) degree angle. Apply this property for the sides to solve the two given problems,
4.
It is given that the side opposite the (30) degree angle has a measure of (8) units. One is asked to find the measure of the other two sides.
The measure of the side opposite the (60) degree side is equal to the measure of the side opposite the (30) degree angle times (
). Thus the following statement can be made,

The measure of the side opposite the (90) degree angle is equal to twice the measure of the side opposite the (30) degree angle. Therefore, one can say the following,

5.
In this situation, the side opposite the (90) degree angle has a measure of (6) units. The problem asks one to find the measure of the other two sides,
The measure of the side opposite the (60) degree angle in a (30-60-90) triangle is half the hypotenuse times the square root of (3). Therefore one can state the following,

The measure of the side opposite the (30) degree angle is half the hypotenuse (the side opposite the (90) degree angle). Hence, the following conclusion can be made,

Answer:
the answer you are looking for is true
You have 6 choices for where to place the H, 5 choices for the A, 4 choices for the E, and 3 choices for the R
(and then the 2 T's go in the remaining places).
This gives 6⋅5⋅4⋅3=360 choices.
Answer:
r = 0.0424 cm (3sf)
Step-by-step explanation:
it makes 150 rev/sec
1 revolution = 1 circumference = 2pi*r
so every second the spool goes through 2*pi*r*150 of distance
we know that the rate of pulling is 40cm/sec
so 2pi*r*150 = 40
r = 40/(2pi*150), which is 0.04244131816 cm.
check: Circumference is 2pi*r = 0.2666
now multiply by 150rev/sec = 40 cm/sec