Why is a river a gift to a desert land

according to the history of psychology reading, a behaviorist psychologist and a cognitive psychologist would most likely argue

Fofino [41]

According to the history of psychology reading, a behaviorist psychologist and a cognitive psychologist would most likely argue about whether: the capacity of a dog to learn tricks is related to its comprehension of human language.

All actions are learned by conditioning, and conditioning takes place through contact with the environment, according to the behaviourist theory of learning. Behaviorists contend that environmental cues influence our behaviour.

Cognitive psychologists study the internal workings of the mind, including memory, perception, learning, and language. They are interested in how individuals comprehend, identify, and solve issues as well as how they make judgments. These psychologists concentrate on how individuals acquire, process, and remember information.

Dogs can understand human body language and tone. Our dogs are more intelligent than merely "Sit," "Stay," and "Walk." Many words may be taught to them, and when we speak them in the right tone, they can understand the meaning even better.

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4 0

2 years ago

What were two reasons that the Russian army suffered incredible losses during WW1?

Naya [18.7K]

Well, I am Russian, so you are getting this STRAIGHT from a source:
The two reasons were hunger and lack of medicine;
At that time, Russia's government were mostly dictators, and stole a LOT of food from the people, and a LOT of harvests & crops from the farmers for businesses;
Medicine was EXTREMELY expensive, and of course, the soldiers were treated WORSE than the people..........
So when they called for donations, the citizens BARELY were able to support themselves, so there was almost NOTHING to give to the soldiers!
Now, there were SOME food and medicine saved for soldiers, but it rationed QUITE QUICKLY!
So MANY soldiers were ill really fast, but due to the VERY skillful and useful techniques they learned to fight in the war, they still survived, (of course, there were soldiers who died too, but a MAJORITY of the Russians won).
I hope I helped, and PLEASE choose my answer as the Brainliest!
Thank you! =D

8 0

3 years ago

In ancient Athens, how were citizens compensated for their participation in the Assembly or on juries?

Ray Of Light [21]

Answer:

FIRST: You had tell the person that you were going to start an action against them to be heard in "court". You had to bring witnesses with you so your witnesses could testify that the person was told why you were bringing an action, and that you had given this person a date, time, and location that they had to appear in court to defend themselves.

SECOND: You had to post a written notice near the courthouse that clearly stated the names of both parties, the charges, and the date, time, and location of your first trip to court on this action.

FIRST TIME IN COURT: The first trip gave both parties a chance to speak before a judge. If the judge felt there was enough cause, that judge would assign a trial date. That trial date had to be posted as well.

JURY SELECTION, TRIAL BY JURY: To be on a jury, you had to be a citizen. You had to be over 30 years of age. You had to swear that you would be fair to both sides. You did get paid. Juries were selected from volunteers. The number of jurors could be huge. Some trials had as many as 500 jurors who had volunteered to judge a case. Only the jury could bring in a decision that someone was guilty or innocent. The judge only kept order, but could not decide a trial outcome.

THE TRIAL: Both sides presented their case. Then the jurors voted. Majority ruled.

PUNISHMENT: Punishments varied. If found guilty, both sides, the person bringing the charge and the person being charged, suggested a punishment. The jury could not choose a third choice. They had to choice one suggestion or the other.

Explanation:

6 0

3 years ago

If the midlife crisis is reframed as a normative, midlife transition, empirical support for this hypothesis might be:_____.

ss7ja [257]

If the midlife crisis is reframed as a normative, midlife transition, empirical support for this hypothesis might be: equal proportions of emerging, young, and middle-aged adults working on their identity.

"Midlife" occurs roughly between the ages of 40 and 60. One prevalent misconception about this time in life is that you should anticipate going through a midlife crisis, or inner conflict about your identity, choices in life, and mortality.

In the 1960s, psychoanalyst Elliott Jacques first used the phrase "midlife crisis." Patients in their mid- to late-30s appeared to experience a depressed phase and abrupt lifestyle changes as they came to terms with their death, according to Jacques.

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4 0

2 years ago

Why did the professional dog walker go out of business math worksheet answers?

Gelneren [198K]

Why Did the Professional Dog Walker ao Out of business, math worksheet Answers:

Q1. sin27° = x/8

Solution:

We have to solve for x, therefore, we will rearrange the given equation for x.

We get,
x = 8 × sin27°

Using the calculator,

sin27° = 0.45

Now substitute the value of sin27° into the main equation.

we get,
x = 8 × 0.45
x = 3.63 (rounded to the nearest hundredth)

Q2. tan 18° = n / 75

Solution:
We have to solve for n, therefore, we will rearrange the given equation for n.
We get,
n = 75 × tan 18°
Using the calculator,
tan 18° = 0.32
Now substitute the value of tan 18° into the main equation.
we get,
x = 75 × 0.32
x = 24.37 (rounded to the nearest hundredth)

Q3. sin40° = 4 / a

Solution: We have to solve for a, therefore, we will rearrange the given equation for a.
We get,
a = 4 ÷ sin40°
Using the calculator,
sin40° = 0.64
Now substitute the value of sin40° into the main equation.
we get,
a = 4 ÷ 0.64
a = 6.25 (rounded to the nearest hundredth)

Q4. cos5° = 92 / y

Solution: We have to solve for y, therefore, we will rearrange the given equation for y.
We get,
y = 92 ÷ cos5°
Using the calculator,
Cos5° = 0.99
Now substitute the value of cos5° into the main equation.
we get,
y = 92 ÷ 0.99
y = 92.92 (rounded to the nearest hundredth)

Q5: Given the shape attached, therefore, using the triangle given, we have:
Angle of elevation = 35°
length of Opposite side to the angle = x
Length of Hypoteneus = 12
Calculations:
Using the SOH CAH TOA rules:
SOH stands for SineФ = Opposite ÷ Hypotenuse.

CAH stands for CosineФ = Adjacent ÷ Hypotenuse.

TOA stands for TangentФ = Opposite ÷ Adjacent.

Hence,

SineФ = Opposite ÷ Hypotenuse

Substituting the values:

Sine35° = x ÷ 12

0.5735 = x ÷ 12

x = 0.5735 × 12

x = 6.88 (rounded to the nearest hundredth)

Q6: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 54°
length of the adjacent side to the angle = x
Length of Hypoteneus = 30
Calculations:
Using the SOH CAH TOA rules:

Hence,

CosineФ = Adjacent ÷ Hypotenuse

Substituting the values:

Cos54° = x ÷ 30

0.5877 = x ÷ 30

x = 0.5877 × 30

x = 17.63 (rounded to the nearest hundredth)

Q7: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 22°
length of the adjacent side to the angle = 85
length of the opposite side to the angle = x
Calculations:

Using the SOH CAH TOA rules:

Hence,

TangentФ = Opposite ÷ Adjacent

Substituting the values:

tan22° = x ÷ 85

0.4040 = x ÷ 85

x = 0.4040 × 85

x = 34.34 (rounded to the nearest hundredth)

Q8: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 16°
length of the opposite side to the angle = x
Length of Hypoteneus = 14
Calculations:
Using the SOH CAH TOA rules:
Hence,

CosineФ = Adjacent ÷ Hypotenuse

Substituting the values:

Sine16° = x ÷ 14

0.2756 = x ÷ 14

x = 0.2756 × 14

x = 3.86 (rounded to the nearest hundredth)

Q9: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 65°
length of the adjacent side to the angle = 9
length of the opposite side to the angle = x
Calculations:
Using the SOH CAH TOA rules:
Hence,

TangentФ = Opposite ÷ Adjacent

Substituting the values:

tan65° = x ÷ 9

2.1445 = x ÷ 9

x = 2.1445 × 9

x = 19.30 (rounded to the nearest hundredth)

Q10: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 51°
length of the adjacent side to the angle = x
Length of Hypoteneus = 70
Calculations:
Using the SOH CAH TOA rules:
Hence,

CosineФ = Adjacent ÷ Hypotenuse

Substituting the values:

Cos51° = x ÷ 70

0.6293 = x ÷ 70

x = 0.6293 × 70

x = 44.05 (rounded to the nearest hundredth)

Q11: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 36°
length of the opposite side to the angle = 15
Length of Hypoteneus = x
Calculations:
Using the SOH CAH TOA rules:
Hence,

CosineФ = Adjacent ÷ Hypotenuse

Substituting the values:

Sine36° = 15 ÷ x

0.5877 = 15 ÷ x

x = 15 ÷ 0.5877

x = 25.52 (rounded to the nearest hundredth)

Q12: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 60°
length of the adjacent side to the angle = x
length of the opposite side to the angle = 100

Calculations:
Using the SOH CAH TOA rules:

Hence,

TangentФ = Opposite ÷ Adjacent

Substituting the values:

tan65° = 100 ÷ x

2.1445 = 100 ÷ x

x = 100 ÷ 2.1445

x = 46.63 (rounded to the nearest hundredth)

Q13: When a 25-ft ladder is leaned against a wall, it makes a 72° with the ground. How high up on wall does the ladder reach?

Solution: Given the shape attached, therefore, using the triangle given, we have:

The angle of elevation from the ground = 72°
length of the wall opposite to the angle = X
Length of ladder (Hypoteneus) = 25 feet

Calculations:
Using the SOH CAH TOA rules:
Hence,

SineФ = Opposite ÷ Hypotenuse

Substituting the values:

Sine72° = x ÷ 25

0.9510 = x ÷ 25

x = 25 ÷ 0.9510

x = 23.77 (rounded to the nearest hundredth)

ANSWERS TO QUESTION 14 AND 15 ARE ATTACHED

7 0

4 years ago