Answer - D.
you basically find the equation of the line first and eliminate the wrong answers...
Strategy: before u do any of this, label your coordinates as (X1,Y1) and (X2,Y2) and u can choose any of ur points to be as x1 or x2 or y1 or y1...
basically, I'll choose (6,7) as (x1,y1) and (2,-1) as (x2,y2). SO,
First you have to find the gradient (m) of the line.
you do this by using the formula m = Y2-Y1 / X2-X1 (where '/' is division sign) ....
Put the numbers in their respective places and your gradient will be 2x. we put the x after our number to represent it as a gradient as the straight line formula is y = mx+c and you've found the m.
NOW.
use the formula Y-Y1=m(x-x1) to find the equation of the line.Again u can use any Y1 and X1 here but remember your m is 2
replace the digits and solve...Hopefully you'll get sth like this if you use the points (6,7):
Y-7 = 2(x-6) ....
y=2x-12+7...
Y=2x-5! <<<< this is your straight line equation!
Now all u gotta do is rearrange all your options into y = mx+c.
D. is incorrect as it gives us y=2x+5 and not y = 2x-5 unlike the others
Hope you get it!
Answer:
60%
Step-by-step explanation:
Step-by-step explanation:
please mark me as brainlest
Answer:
single-channel, multi -phase
Step-by-step explanation:
The concept known as '' Queuing'' is not only important in the mathematical aspect alone but it is also useful in economic matters as signifies the abundance of resources that is when we have queues it means the reason for it is that the available resources is not enough.
From the question above we have that there are 3 individual car wash stalls, it is also given that the customers wait in a single line before choosing the next available stall. This means that there is only a single-channel.
Then, we have that from the single line initially, the queues then moves to multi -phase that is to 3 individual car wash stalls.
Answer:
7
Step-by-step explanation:
[(1/3 – 1/9)² + (1/3)³] : (1/3)⁴
Next, we shall simplify (1/3 – 1/9)². This is illustrated below:
(1/3 – 1/9)² = ((3 – 1)/9)² = (2/9)²
[(1/3 – 1/9)² + (1/3)³] : (1/3)⁴
= [(2/9)² + (1/3)³] : (1/3)⁴
= [4/81 + 1/27] : 1/81
= [(4 + 3)/81 ] : 1/81
= 7/81 : 1/81
= 7/81 ÷ 1/81
Invert
= 7/81 × 81/1
= 7
