Answer:
x<15
Step-by-step explanation:
-(x - 1) + 20 <-3(x - 3)
-x + 1 + 20 <-3x + 9
-x + 21 < -3 + 9
-x < -3 + 9 - 21
-x÷ -1 < -15 ÷ -1
x > 15
The probability of winning exactly 21 times is 0.14 when the probability of winning the arcade game is 0.659.
We know that binomial probability is given by:
Probability (P) = ⁿCₓ (probability of 1st)ˣ x (1 - probability of 1st)ⁿ⁻ˣ
We are given that:
Probability of winning on an arcade game = P(A) = 0.659
So, the Probability of loosing on an arcade game will be = P'(A) = 1 - 0.659 = 0.341
Number of times the game is being played = 30
We have to find the Probability of winning exactly 21 times.
Here,
n = 30
x = 21
P(A) = 0.659
P'(A) = 0.341
Using the binomial probability formula, we get that:
Probability of winning exactly 21 times :
P(21 times) = ³⁰C₂₁ (0.659)²¹ x (0.341)⁷
P( 21 times ) = 0.14
Therefore, the probability of winning exactly 21 times is 0.14
Learn more about " Binomial Probability " here: brainly.com/question/12474772
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Answer:
∠ WXY = 127° is the ansewer, hope this helped!
Step-by-step explanation:
Answer:
One
Step-by-step explanation: