Find 3 consecutive integers whose sum is 573
1 answer:
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If we use
, +2, and +4 as our 3 consecutive odd integers, we get this equation: + + 2+ + 4 = 573. After putting that into simpler terms, we get this: 3 + 6 = 573. Then we subtact 6 from both sides. We get 3 = 567. 567 ÷ 3 = 189.
x = 189.
If this helped, please mark this answer the brainliest. Thanks!
If we use
x = 189.
If this helped, please mark this answer the brainliest. Thanks!
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Answer:
= 5n - 1
Step-by-step explanation:
There is a common difference between consecutive terms , that is
9 - 4 = 14 - 9 = 19 - 14 = 5
This indicates the sequence is arithmetic with nth term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 4 and d = 5 , then
= 4 + 5(n - 1) = 4 + 5n - 5 = 5n - 1
Answer:
AG = 4
AH = 21
EC = 12
CH = 5
HE = 7
Step-by-step explanation:
<u><em>The complete question is</em></u>
The diameters of circles A, C and E are 32 cm, 24 cm and 14 cm respectively.
Which of the following statements are true? Select all that apply.
•AG = 4
•GC = 10
•AH = 21
•EC = 12
•EH = 5
•CH = 5
•HE = 7
The picture of the question in the attached figure
<u><em>Verify each statement</em></u>
1) AG = 4
we know that
----> radius of circle A
----> radius of circle C
substitute
therefore
The statement is true
2) GC = 10
we know that
----> radius of circle C
therefore
The statement is false
3) AH = 21
we know that
we have
----> radius of circle A
----> radius of circle C
----> radius of circle E
so
therefore
The statement is true
4) EC = 12
we know that
----> radius of circle C
therefore
The statement is true
5) EH = 5
we know that
----> radius of circle E
therefore
The statement is false
6) CH = 5
we know that
----> radius of circle C
----> radius of circle E
so
therefore
The statement is true
7) HE = 7
we know that
----> radius of circle E
therefore
The statement is true
