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3 years ago

I kinda got confused on this one 25z - 8z + (-3z)

Mathematics

2 answers:

Gala2k [10]3 years ago

8 0

14z

First do the parenthesis and then subtract then add

otez555 [7]3 years ago

7 0

Answer:

The answer is 14z

Step-by-step explanation:

25z - 8z + (-3z)

-8z + (-3z) is the same thing as -8z - 3z, which equals -11z,

25z - 11z = 14z

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Inverse function of y=f(x)=1-2/x^3

tia_tia [17]

Answer:

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Step-by-step explanation: not good at this stuf

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3 years ago

What is the measure of angle XYZ?

Ierofanga [76]

Answer:

63degrees

Step-by-step explanation:

Using the theorem which states that the measure of angle at the vertex is half the angle of its intercepted arc.

Given

angle of its intercepted arc = 126 degree

Required

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3 years ago

Why can't 1.07 pounds of sugar be compared to 1.23 cups of sugar?

Anuta_ua [19.1K]

Answer:

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Step-by-step explanation:

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3 years ago

Use the identity (x+y)(x2−xy+y2)=x3+y3 to find the sum of two numbers if the product of the numbers is 10, the sum of the square

professor190 [17]

Answer:

The sum of two numbers is 7.

Step-by-step explanation:

Given : the product of the numbers is 10, the sum of the squares of the numbers is 29, and the sum of the cubes of the numbers is 133.

Using identity $(x+y)(x^2-xy+y^2)=x^3+y^3$ and given details, we have to find the sum of two numbers.

Since, given that the product of the numbers is 10 that is $xy=10$

Also, given the sum of the squares of the numbers is 29 that is $x^2+y^2=29$

and the sum of the cubes of the numbers is 133 that is $x^3+y^3=133$

Using, the given identity $(x+y)(x^2-xy+y^2)=x^3+y^3$ ,

Substitute, the given values, we have,

$(x+y)(29-10)=133$

Simplify , we get,

$(x+y)(19)=133$

Divide both side by 19, we have,

$(x+y)=7$

Thus, the sum of two numbers is 7.

7 0

3 years ago

Read 2 more answers

If f(x, y) = xy, find the gradient vector ∇f(2, 5) and use it to find the tangent line to the level curve f(x, y) = 10 at the po

hammer [34]

Answer:

Step-by-step explanation:

check attachment

f(x,y)=xy Δf(2,5)

fx=y = 5

fy=x = 2

Gradient Vector:

<5,2>

Tangent Vector:

0=fx(x-2) + fy(y-5)

0=5(x-3) + 2(y-2)

11=5x+2y

8 0

3 years ago