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zavuch27 [327]
3 years ago
11

Using Pythagorean Theorem what is the square root of the third side ?

Mathematics
1 answer:
IrinaVladis [17]3 years ago
5 0
Pythagorean theorm is a^2+b^2=c^2
so 10^2+ 24^2 =c^2
100+576=c^2
676=c^2
26=c
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Points (2,7) ana (5,10).
Mrrafil [7]

Answer:

Below.

Step-by-step explanation:

3x + 5y = 15

Subtract 3x from both sides:

5y = -3x + 15

Divide through by 5:

y = -3/5 x + 3   <-----------slope-intercept form

4 0
3 years ago
Solve the system graphically:<br><br><br> b <br><br> x−y=0<br> 2x+3y=−5<br> x=<br> y=
vlabodo [156]

Answer:

(-1,-1)

Step-by-step explanation:

x=y

2x+3x=-5

x=-1

y=-1

6 0
3 years ago
Is 2/3 greater than 3/5
Zinaida [17]
Yes because the larger the bottom number the smaller the amount. :)
8 0
3 years ago
Read 2 more answers
Please answer the question and leave an explanation on how to solve each part. Thank you in advance!
horsena [70]

The solutions are

  • it is going to take 15.9 months to raise 10000 dollars
  • You will have $37.31 after you have bought the car
  • The money deficit would be $37.31

<h3>How to solve the question</h3>

a. 10000 = 9359.08e(0.05)

e⁰⁰⁵ = 10000/9359.08

= 0.05 = ln(10000/9359.08)

= 1.325 years

convert to months = 15.9 months

Hence it is going to take 15.9 months to raise 10000 dollars

b. 9359.08 x e^(0.05 x1.25)

= 9962.69

10000 - 9962.69

= $37.31

You will have $37.31 after you have bought the car

c. The money loss and the deficit would be same as above $37.31

d. ln(e^a) = a

We can clearly see that the money cannot be raised in the 15 months from $ 9359.08. there is a deficit amount of $37.31

Read more on compound interest here: brainly.com/question/24924853

#SPJ1

3 0
1 year ago
USING the Midpoint Formula , POINT A is at (-3,-5) and point M is at (-0.5,0). what are the coordinates of point B
Rasek [7]

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{-3}~,~\stackrel{y_1}{-5})\qquad B(\stackrel{x_2}{x}~,~\stackrel{y_2}{y}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{x-3}{2}~~,~~\cfrac{y-5}{2} \right)~~=~~\stackrel{\stackrel{Midpoint}{M}}{(-0.5~,~0)}\implies \begin{cases} \cfrac{x-3}{2}=-0.5\\[1em] x-3=-1\\ \boxed{x= 2}\\ \cline{1-1} \cfrac{y-5}{2}=0\\[1em] y-5=0\\ \boxed{y=5} \end{cases}

7 0
3 years ago
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