Using Pythagorean Theorem what is the square root of the third side ?
1 answer:
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Answer:
1. 45.71 miles
2. 10 miles
3. 89.43 miles
4. 0.79 hr
5. 0.025 hr
Step-by-step explanation:
speed = distance/time
After 4 hrs Beverly was 200 miles from home , however she had spent 0.5hr travelling for 20 miles prior to getting to the highway.
Therefore;
Constant speed before Highway = 20/0.5 = 40 miles/hr
Constant speed at Highway = = 51.43 miles/hr
1. in 1 hr beverly will have travelled;
⇒ (20 miles in 0.5 hr ) + (0.5 hr at speed 51.43 miles/hr)
⇒ 20 + (0.5 x 51.43) = 45.71 miles
2. In 0.25 hr beverly had not reached the highway
⇒ distance = speed x time
⇒ distance = 40 x 0.25 = 10 miles
3. in 1.85 hrs beverly will have travvelld;
⇒ (20 miles in 0.5 hr ) + (1.35 hr at speed 51.43 miles/hr)
⇒ 20 + 69.43 = 89.43 miles
4. Time taken to get to 35 miles
⇒ (20 miles in 0.5 hr ) + (15 miles at speed 51.43 miles/hr)
⇒ 0.5hr + (15/51.43) hr = 0.79 hr
5. Time taken to travel 1 mile
⇒ time = distance / speed = 1 mile / 40 miles/hr
⇒ time = 0.025 hr
First, we need to work out the total number of students who were being surveyed.
We know that half of the students has two pets. The rest of the students make up the other half. So, we have 3 students + 2 students + 8 students = 13 students that make half of the sample population
That means total number of students being surveyed is 13+13=26 students
Then we work out the probability
P(One pet) = 8/26 = 4/13
P(Two pets) = 1/2
P(Three pets) = 3/26
P( Four pets) = 2/26 = 1/13
The probability distribution is shown in the table below. Let
be the number of pets and 
is the probability of owning the number of pets
We know that half of the students has two pets. The rest of the students make up the other half. So, we have 3 students + 2 students + 8 students = 13 students that make half of the sample population
That means total number of students being surveyed is 13+13=26 students
Then we work out the probability
P(One pet) = 8/26 = 4/13
P(Two pets) = 1/2
P(Three pets) = 3/26
P( Four pets) = 2/26 = 1/13
The probability distribution is shown in the table below. Let