17) f(x) = 16/(13-x).
In order to find domain, we need to set denominator expression equal to 0 and solve for x.
And that would be excluded value of domain.
13-x =0
Adding x on both sides, we get
13-x +x = x.
13=x.
Therefore, domain is All real numbers except 13.
18).f(x) = (x-4)(x+9)/(x^2-1).
In order to find the vertical asymptote, set denominator equal to 0 and solve for x.
x^2 -1 = 0
x^2 -1^2 = 0.
Factoring out
(x-1)(x+1) =0.
x-1=0 and x+1 =0.
x=1 and x=-1.
Therefore, Vertical asymptote would be
x=1 and x=-1
19) f(x) = (7x^2-3x-9)/(2x^2-4x+5)
We have degrees of numberator and denominator are same.
Therefore, Horizontal asymptote is the fraction of leading coefficents.
That is 7/2.
20) f(x)=(x^2+3x-2)/(x-2).
The degree of numerator is 2 and degree of denominator is 1.
2>1.
Degree of numerator > degree of denominator .
Therefore, there would no any Horizontal asymptote.
It is impossible because it's base is not circular. A solid of revolution is <span>obtained by rotating a </span>plane curve<span> around some </span>straight line, that is, <span>the </span>axis of revolution that lies on the same plane. The closest to a square pyramid applying this concept is by rotating a right triangle around the opposite or adjacent side (the axis), but the shape that you get is a straight circular cone.
I think i only get some of it. this is what i did
x = -3 to 4y = 0.3 to 3if we use -3 and 3a < -1 < b
a= -2 to infiniteb= 0 to infinite
Answer: 79 degrees
Step-by-step explanation:
4x+1 + 3x+4 = 180
7x + 5 = 180
7x = 175
x = 175:7 = 25
m8 = 3x + 4 = 3*25 + 4 = 79
Sorry but can we get a better shot of the paper can barley see it
