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dalvyx [7]
3 years ago
14

23=1/3b-2+4/3bwhat is the value of b?​

Mathematics
1 answer:
mash [69]3 years ago
4 0

Answer:

b=15

Step-by-step explanation:

You might be interested in
. Express the ratios in its simplest form (a) 15:12 (b) 42:1
telo118 [61]

Answer:

See answers below

Step-by-step explanation:

Given the following ratios. We are to express them in their simplest forms

15:12

= 15/12

= (3*5)/(3*4)

= 3/3 * 5/4

= 5/4

b) 42:1

= 42/1

= 42

Given that  2:x :: 4:6​

2/x = 4/6

Cross multiply

4x = 2*6

4x = 12

x = 12/4

x = 3

Hence the value of x is 3

7 0
2 years ago
$4.30 for make up; 40% dicount; 6% tax
Wittaler [7]
$4.30X40%=1.72
4.30-1.72=2.58
2.58X6%=.15
2.58+.15=2.73
Final price: $2.73
6 0
3 years ago
Which of the following actions would be favored by a government that supports a mercantilist economy?
anygoal [31]
A mercantilism system sought to enrich the country by restraining imports and encouraging exports. So I believe ur answer is gonna be B.
3 0
3 years ago
Read 2 more answers
Thomas brings over 1/2 of his marble collection. He divides these marbles equally among 3 friends. What fraction of Thomas's ent
aleksley [76]

Answer:

Each of the three friends will get one-sixth of the Thomas's enitre marble collection.

Step-by-step explanation:

Fraction of the total marble collection brought by Thomas = \frac{1}{2}

Now, Thomas divides these marbles equally among his three friends. So, each of the three friends will get one-third of the total marble collection brought by Thomas.

Fraction of total marble collection got by each friend = \frac{1}{3} \;of\;fraction\;of\;total\;marble\;collection\;brought\;by\;Thomas

= \frac{1}{3}\times\frac{1}{2}=\frac{1}{6}

∴ Each of the three friends of Thomas will get one-sixth of his entire collection of marbles.

7 0
3 years ago
5x+7y=31 2x+4y=16 Which of the following systems could be used to solve the given system of equations by the addition method? 10
Pani-rosa [81]
Equation 1: 5x+7y=31
Equation 2: 2x+4y=16

We can either use the 'elimination' method or the 'substitution' method to solve this simultaneous equation.

In some cases one method is easier to use than the other. For this one, it would be easier to use the elimination method

We need to eliminate either the 'x' or the 'y' to begin with. Say we want to eliminate the 'x' terms, then the next step is to make the constant the same

Equation 1: the constant of 'x' is 5
Equation 2: the constant of 'x' is 2

To make the two constants the same, think of common multiple. The lowest common multiple for 5 and 2 is 10

Equation 1:  Multiply all terms by 2 to achieve 10x
Equation 2: Multiply all terms by 5 to achieve 10x

Equation 1: 10x+14y=62
Equation 2: 10x+20y=80

Once the constant of 'x' is the same, then we can start the elimination process. Since our aim is to eliminate, one of the 'x' need to be in negative form. We can either multiply Equation 1 or Equation 2 by (-1)

Equation 1: -10x - 14y = -62
Equation 2: 10x + 20y = 80

Hence the correct answer is: Third option




3 0
3 years ago
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