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lorasvet [3.4K]
3 years ago
12

Please help how do i find the area of the shape?

Mathematics
1 answer:
Orlov [11]3 years ago
6 0

Answer:

Do not listen to the other answer! Here is how you solve that.

Step-by-step explanation:

For the semicircle, here is the formula for area: A= \frac{1}{2}(\pi r^2)

For the triangle, here is the formula for area:A=\frac{1}{2}(bh)

Then, add.

So,

Triangle:

A=\frac{1}{2}(9*12)

A=54

Semicircle:

A=\frac{1}{2}(\pi 6^2)

A=18\pi

Your answer is Area = 54 + 18\pi

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The hypotenuse of a 45°-45°-90° triangle measures 128 cm. A right triangle is shown. The length of the hypotenuse is 128 centime
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Answer:

64√2 or 64 StartRoot 2 EndRoot

Step-by-step explanation:

A 45-45-90 traingle is a special traingle.  Let's say one of the leg of the triangle is x. The other one is also x because of the isosocles triangle theorem.  Therefore, using the pytagorean theorem, you find that x^2+x^2=c^2.  2(x)^2=c^2.  You then square root both sides and get c= x√2.  

Therefore, the two legs are x and the hypotenuse is x√2.  x√2=128 because the question says that the hypotenuse is 128.  Solve for x by dividing both sides by √2.  X=128/√2.  You rationalize it by multiplying the numberator and denominator of the fraction by √2.  √2*√2= 2.

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3 years ago
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Please help me , thank you
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Answer:

80 degrees

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one half of the circle makes a straight line and that will equal 180 degrees so 60+45=105

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A point has 0 dimensions. It has no length, width, or depth.

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~An emotional teen who helps others with joy

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