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posledela
4 years ago
5

How many times greater is the value represented by the digit 3 in 437,291 than the value represented by the digit 3 in 583,426?

Mathematics
1 answer:
Orlov [11]4 years ago
8 0

Answer:

10 times greater

In the first number, 3 represents 30,000, but in the second number 3 represents 3,000 so 30,000 is 10 times greater

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A store has 7 red shirts, 15 black shirts, 13 white shirts, and 5 green shirts. Select the portion of the shirts that are black.
makkiz [27]

Answer:

g

Step-by-step explanation:

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3 years ago
A drunk person is walking on the road. With probability 0.6 he takes a step forward and with probability 0.4 he takes a step bac
Molodets [167]

If a person after 10 steps is at his starting position, then this person takes 5 steps forward and 5 steps backward.

This is a binomial distribution with

  • probability to take step forward p=0.6;
  • probability to take step backward q=0.4;
  • n=10.

Then

Pr(\text{5 steps forward and 5 steps backward})=C_{10}^5p^5q^5=\\ \\=\dfrac{10!}{5!(10-5)!}\cdot (0.6)^5\cdot (0.4)^5=\dfrac{10!}{5!\cdot 5!}\cdot (0.6\cdot 0.4)^5=\\ \\=\dfrac{5!\cdot 6\cdot 7\cdot 8\cdot 9\cdot 10}{5!\cdot 2\cdot 3\cdot 4\cdot 5}\cdot (0.24)^5=7\cdot2\cdot 9\cdot 2\cdot (0.24)^5=252\cdot (0.24)^5=0.2006581248.

Answer: 252\cdot (0.24)^5=0.2006581248.

6 0
3 years ago
the ratio of mystery books to fiction books is 2 to 3. if there are 12 mystery books, how many fiction books are there
LiRa [457]

Answer: 56

Step-by-step explanation:

8 0
3 years ago
A ship leaves the port of Miami with a bearing of S80°E and a speed of 15 knots. After 1 hour, the ship turns 90° toward the sou
CaHeK987 [17]

Answer:

The bearing is N 55.62° W

Step-by-step explanation:

ship leaves the port of Miami with a bearing of S80°E and a speed of 15 knots.

It then turns 90° towards the south after one hour.

Still maintain the same speed and direction for two hours.

The bearing is just the angle difference from the ship current location to where it started.

Let the speed be km/h

Distance covered in the first round

= 15*1

= 15km

Distance covered in the second round

=15*2

= 30 km

Angle at C = (90-80)+90

Angle at C = 10+90= 100

Let the distance between the port and the ship be c

C²= a² + b² -2abcos

C²= 15²+30²-2(15)(30)cos 100

C²= 225+900+156.28

C²= 1281.28

C= 35.8 km

Using sine formula

30/sin x= 35.8/sin 100

30/35.8 * sin 100 = sinx

0.838*0.9848= sin x

0.8253= sin x

Sin ^-1 0.8253 = x

55.62° = x

The bearing is N 55.62° W

8 0
3 years ago
Can you guys help me with a math problem
quester [9]

Answer:

680.. that is if we are only doing 4 weeks = a month but yeah :)

Step-by-step explanation:

3 0
3 years ago
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