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zheka24 [161]
3 years ago
6

Answer plzzzz I need it ok

Mathematics
1 answer:
Mariana [72]3 years ago
4 0

Answer:

There are 26 different possible outcomes. the probability of the computer choosing the first letter of your name is 1 out of 26.

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A meteorologist is studying the speed at which thunderstorms travel. A sample of 10 storms are observed. The mean of the sample
dezoksy [38]

Answer:

The 95% confidence interval for the true mean speed of thunderstorms is [10.712, 13.688].

Step-by-step explanation:

Given information:

Sample size = 10

Sample mean = 12.2 mph

Standard deviation = 2.4

Confidence interval = 95%

At confidence interval 95% then z-score is 1.96.

The 95% confidence interval for the true mean speed of thunderstorms is

CI=\overline{x}\pm z*\frac{s}{\sqrt{n}}

Where, \overline{x} is sample mean, z* is z score at 95% confidence interval, s is standard deviation of sample and n is sample size.

CI=12.2\pm 1.96\frac{2.4}{\sqrt{10}}

CI=12.2\pm 1.487535

CI=12.2\pm 1.488

CI=[12.2-1.488, 12.2+1.488]

CI=[10.712, 13.688]

Therefore the 95% confidence interval for the true mean speed of thunderstorms is [10.712, 13.688].

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3 years ago
How many solutions does the system have?
Ipatiy [6.2K]
It’s has NO SOLUTION.
8 0
3 years ago
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For each of 2 ≤ n ≤ 5, compute c(n, 0) + c(n, 2) + ⋅⋅⋅ + c(n, 2k), where 2k is largest even integer ≤ n, and compute c(n, 1) + c
Ksivusya [100]
Denote C(n,m)=\dbinom nm. Then

n=2\implies\displaystyle\binom20+\binom22=1+1=2
n=3\implies\displaystyle\binom30+\binom32=1+3=4
n=4\implies\displaystyle\binom40+\binom42+\binom44=1+6+1=8
n=5\implies\displaystyle\binom50+\binom52+\binom54=1+10+5=16

In general, it would appear that

\displaystyle\sum_{k=0}^{2\lfloor\frac n2\rfloor}\binom n{2k}=2^{n-1}

On the other hand,

n=2\implies\displaystyle\binom21=2
n=3\implies\displaystyle\binom31+\binom33=3+1=4
n=4\implies\displaystyle\binom41+\binom43=4+4=8
n=5\implies\displaystyle\binom51+\binom53+\binom55=5+10+1=16

so that in general, we also get

\displaystyle\sum_{k=0}^{2\lfloor\frac{n-1}2\rfloor+1}\binom n{2k+1}=2^{n-1}
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3 years ago
two runners are competing in a race. one runner averages a pace of 7 minutes per mile and finishes the race in 28 minutes. the s
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7minutes and 30 seconds
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Explain how you would find 2 times 2 1/3 using the distributive property
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You would do 2(2) + 2(1/3) = 4 2/3.
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