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3 years ago

A hiker is making his way up a mountain. After resting for a night, he travels with a group toward the top of the mountain

Mathematics

1 answer:

andrezito [222]3 years ago

5 0

Answer:

I don´t understand

Step-by-step explanation: your thing does not make since

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Help please............

lesantik [10]

Lilla got 21/25 meaning she only missed 4 questions which means she got a 96/100. Tim scored 41/50 meaning he missed 9 questions meaning he got a 91/100 therefore being the reason Lilla got a higher score than Tim being that she has a 96 versus his 91. Hope that helps!!!

4 0

3 years ago

A recent study examined the association between high blood pressure and increased risk of death from cardiovascular disease. The

zalisa [80]

<span>Find the odds of a man with high blood pressure dying from cardiovascular disease. 55 p .0165 3338 = p .0165 .0165 .0168 1 p 1 .0165 .9835

Do the same for a man with low blood pressure. 21 p .0079 2676 = = p .0079 .0079 .00796 1 p 1 .0079 .9921 = = = − − ----->

Calculate the odds ratio with the odds for the high blood pressure group in the numerator. Describe the result in words. HBP LBP odds .0168 odds ratio 2.11 odds .00796 = = = Men with high blood pressure are 2.11 times more likely to die from cardiovascular disease.</span>

7 0

3 years ago

Apply the distributive property to factor out the GCF.<br><br> 18d + 12= _________

stiv31 [10]

Answer:

6(3d+2)

Step-by-step explanation:

8 0

3 years ago

You must reverse the inequality sign when solving this inequality: x + 7 < 4

SSSSS [86.1K]

I'm not 100% sure what you want me to do with this but i hope this helps:

x < -3

or if you want me to flip the sign then the solution becomes

x > -3

7 0

3 years ago

Assume the sample variances to be continuous measurements. Find the probability that a random sample of 25observations, from a n

konstantin123 [22]

Answer:

a) $P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502$

b) $P(13.848$ Step-by-step explanation:

Previous concepts

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

For this case we assume that the sample variance is given by $S^2$ and we select a random sample of size n from a normal population with a population variance $\sigma^2$ . And we define the following statistic:

$T = \frac{(n-1) S^2}{\sigma^2}$

And the distribution for this statistic is $T \sim \chi^2_{n-1}$

For this case we know that n =25 and $\sigma^2 = 6$ so then our statistic would be given by:

$\chi^2 = \frac{(n-1)S^2}{\sigma^2}=\frac{24 S^2}{6}= 4S^2$

With 25-1 =24 degrees of freedom.

Solution to the problem

Part a

For this case we want this probability:

$P(S^2 > 9.1)$

And we can multiply the inequality by 4 on both sides and we got:

$P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502$

And we can use the following excel code to find it: "=1-CHISQ.DIST(36.4,24,TRUE)"

Part b

For this case we want this probability:

$P(3.462 < S^2$

If we multiply the inequality by 4 on all the terms we got:

$P(3.462*4 < 4S^2 < 4*10.745)= P(13.848< \chi^2$ And we can find this probability like this: $P(13.848$ And we use the following code to find the answer in excel: "=CHISQ.DIST(42.98,24,TRUE)-CHISQ.DIST(13.848,24,TRUE)"

8 0

3 years ago