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Delvig [45]
3 years ago
10

Is this right and what's the answer for number 3?

Mathematics
2 answers:
kondaur [170]3 years ago
8 0

Answer: Hello!

the problems are wrong:

in the first problem, you have 38 rocks, and you can separate them into groups of 10 or in single rocks.

You have 4 options to do it:

0 groups of 10, and 38 single rocks.

1 group of ten and (38 - 19) = 28 single rocks

(this is 10 rocks in the group of then + 28 single rocks = 38 total rocks)

2 groups of ten and (38 - 2*10) =  18 single rocks

3 groups of ten and (38 - 3*10) = 8 single rocks

and you can't form more groups of tens because you only have 8 single rocks left at this point.

in the second problem, the case is the same, now you have 30 pieces of felt and you can divide them into groups of 10 or in single pieces.

then the possible options are:

0 groups of ten and 30 single pieces

1 group of ten and (30 - 10) = 20 single pieces

2 groups of ten and (30 - 2*10) = 10 single pieces

3 groups of ten and (30 - 3*10) = 0 single pieces

in the third problem you need to write, similarly as i did, why you organized the rocks or the pieces as you did.

Mumz [18]3 years ago
7 0
That looks great! But say you chose number 2. You could say you organized it by multiplying single packs by the pieces of packs.
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Need help on geometry please right answer only I’m giving out 40 points
Juliette [100K]
Answer: first option 392.699 square feet.


Explanation:

1) The shape of the sidewalk is an ring with exterior radius equal to the radious of the fountain + 5 feet and inner radius equal to the radius of the fountain.

2) The area of such ring is equal to the area of the outer circle less the area of the inner circle (the fountain)

Area of a circle = π × r²

Area of the outer circle: π (10ft +  5 ft)² = π (15 ft)² = 225 π ft²

Area of the inner circle = π (10ft)² = 100 π ft²

Area of the ring  (sidewald) = 225π ft² - 100π ft² = 125π ft² = 392.699 ft²
6 0
3 years ago
Read 2 more answers
What is a 3 2/3 model example?
Annette [7]

I don't have an exact model but this site can help you.


https://learnzillion.com/lesson_plans/7928-use-models-for-division-of-fractions-by-fractions/


I hope this helps you in your studies and have an awesome day!


8 0
2 years ago
A student is trying to solve the system of two equations given below: Equation P: a + b = 6 Equation Q: 4a + 2b = 19 Which of th
Marrrta [24]

Answer:

-4(a + b = 6)

Step-by-step explanation:

Given

a + b = 6

4a + 2b = 19

Required

Eliminate a

Multiply the first equation by -4

-4(a + b = 6)

Add to the second equation

-4(a + b = 6) + (4a + 2b = 19)

Solve brackets

(-4a -4b = -24) + (4a + 2b = 19)

Open bracket

-4a + 4a -4b  + 2b = -24 + 19

-4b  + 2b = -24 + 19

At this point, a has been eliminated;

From the list of given options, the option that answers the question is -4(a + b = 6)

8 0
3 years ago
7. What is the equation of the line that passes through (-1, -4) and (0,5)?
Serga [27]

Answer:

A)y=9x+5

Step-by-step explanation:

If x=-1, y=-4,

  y=9*-1+5=(-9)+5=-4

If x=0, y=5,

  y=9*0+5=5

3 0
2 years ago
In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b
madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding (ax+by)^7 using Binomial expansion, we have that:

(ax+by)^7 =

(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7

= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7

We have that the coefficients of the first two terms are 128 and -224.

For the first term:

=> a^7 = 128

=> a = \sqrt[7]{128}\\ \\\\a = 2

For the second term:

a^6b = -224

b = \frac{-224}{a^6}

b = \frac{-224}{2^6} \\\\\\b = \frac{-224}{64} \\\\\\b = 3.5

Therefore, a = 2, b = 3.5

5 0
3 years ago
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