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Alex
4 years ago
14

Someone please help ASAP!!!!

Mathematics
1 answer:
IrinaVladis [17]4 years ago
4 0
Steps:

A=bh/2

A= (18ft)(6ft)
_______
2
A = 108
____
2
A= 54ft^2
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(x^4+x^3+x+1)/(x^4-x^3+2x^2-x+1)<br> Rút gọn biểu thức
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3 years ago
Someone please help I will mark brainliest
malfutka [58]

Answer:

Yes

Step-by-step explanation:

Yes, because there are two pairs of sides marked as congruent, seen by the line bisectors. And, angles T and S are marked as congruent.

3 0
3 years ago
PLS HELP 15 POINTS
RSB [31]

Anna's balance after writing check #1620 was B) $1606.42

Step-by-step explanation:

Step 1; Whenever you make a payment, make a cash withdrawal the money in your account decreases as you're giving your money to someone else. So the money spent or taken is reduced from the balance in your account.

Whenever you get your paycheck or make a deposit the money you have in your account increases. So the amount of money put in or the money you are paid is added with the balance you have in your account.

Step 2; Anna had a balance of $2,339.27 before writing the check #1620. She withdraws an amount of $732.85 under the description of  the city bank. As she withdrew money, withdrawn money is subtracted from the balance.

Balance after writing the #1620 check = Balance before writing the #1620 check - amount of money withdrawn = $2,339.27 - $732.85 = $1,606.42,

So her balance after writing check #1620 was $1,606.42.

8 0
3 years ago
What times what equals 99
inessss [21]
Answer(s):

9 × 11 = 99

11 × 9 = 99

33 × 3 = 99

3 × 33 = 99

1 × 99 = 99

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Decimals:

6 × 16.5 = 99

I hope these helped!

4 0
3 years ago
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True

A linear recurrence relation involving a sequence of numbers a_n is one of the form

\displaystyle\sum_{k=0}^nc_{n-k}a_{n-k}=c_na_n+c_{n-1}a_{n-1}+\cdots+c_2a_2+c_1a_1=c

where c_1,c_2,\ldots,c_n and c are any fixed numbers.

The given recurrence can be rearranged as

a_n=a_{n-1}+2\implies 1\cdot a_n+(-1)\cdot a_{n-1}=2

A nonlinear recurrence would have a more "exotic" form that cannot be written in the form above. Some example:

a_n+\dfrac1{a_{n-1}}=1

a_na_{n-1}=\pi

{a_n}^2+\sqrt{a_{n-1}}-\left(\dfrac{a_{n-2}}{\sqrt{a_n}}\right)^{a_{n-3}}=0

3 0
4 years ago
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