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bekas [8.4K]
3 years ago
9

Homework 1. (4x3+ 8x2 10x) (12x3 2x2 3x 9)

Mathematics
1 answer:
dem82 [27]3 years ago
7 0
Using PEMAS
4×3=12
8×2=16
12×3=36
2×2=4
3×9=27


12+16+10×36+4+27
28+360+31=419
I believe this is correct, Hope this helps
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-3(x+2)=12. solve for x
bagirrra123 [75]

Steps to solve:

-3(x + 2) = 12

~Distributive Property

(-3 * x) + (-3 * 2) = 12

~Simplify

-3x - 6 = 12

~Add 6 to both sides

-3x - 6 + 6 = 12 + 6

~Simplify

-3x = 18

~Divide -3 to both sides

-3x/-3 = 18/-3

~Simplify

x = -6

Best of Luck!

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Olivia selects marbles from a bag containing 5 red and 7 blue marbles. Which of the following events are independent?
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Answer:

B

Step-by-step explanation:

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Which ordered pairs in the form (x, y) are solutions to the equation
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Answer:    6, 0

Step-by-step explanation:

4(6)=24

5(0)=0

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URGENT!!!! let x= -2, y=4, and z =1/2 evaluate z(y-3x)+x​
lianna [129]

Answer:

The answer is 3.

Step-by-step explanation:

1. You need to substitute the values into the equation

2. You would then have 1/2(4-3(-2))-2

3. Now you have to multiply 3×-2 and you will now have 1/2(4+6)-2

4. Then you have to add what's in the parenthesis and you will have 1/2(10)-2

5. Now multiply 1/2(10) and uou will have 5-2

6. Now subtract 5-2 and that will = 3

(There is also a picture of how I worked it out)

7 0
3 years ago
Refer to the Teaching Psychology (May 1998) study of how external clues influence performance. Two different forms of a midterm
kozerog [31]

Answer:

P(X

P(Y

So for this case we have a higher probability for the red exam so we can conclude that the student is more likely to score below 20% on the difficult questions in the red one.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the scores for the blue exam, and for this case we know the distribution for X is given by:

X \sim N(53,15)  

Where \mu=53 and \sigma=15

We are interested in the probability that P(X<20%)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

And if we replace we got:

P(X

Let Y the random variable that represent the scores for the red exam, and for this case we know the distribution for X is given by:

Y \sim N(39,12)  

Where \mu=39 and \sigma=12

We are interested in the probability that P(Y<20%)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{y-\mu}{\sigma}

And if we replace we got:

P(Y

So for this case we have a higher probability for the red exam so we can conclude that the student is more likely to score below 20% on the difficult questions in the red one.

7 0
3 years ago
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