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kumpel [21]
3 years ago
14

Use the Distributive Property to multiply. 9(4m + 1) A. 36m + 9 B. 45m C. 36m + 1 D. 13m + 9

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
3 0

The distributive property:

a(b + c) = ab + ac

We have

9(4m + 1) = (9)(4m) + (9)(1) = 36m + 9

<h3>Answer: A. 36m + 9</h3>
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Cathy rolls a number cube that is labeled from 1 to 6.
MatroZZZ [7]

Answer: 2/3

Cathy rolls a number cube that is labeled from 1 to 6.

Total outcomes = {1,2,3,4,5,6}

she rolls an even number or a multiple of 3

Outcomes of an even number = {2,4,6}

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so favorable outcomes of even number or a multiple of 3 = {2,3,4,6}

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3 years ago
A partir del término general, calcular los 4 primerostérminos. (Considere que debe asignar
Scorpion4ik [409]

Answer:

4,7,12,19,...

Step-by-step explanation:

<u><em>The question in English is:</em></u>

From the general term, calculate the first 4 terms.  

(Consider that you must assign values to the variable n)

we have

b_n=n^2+3

step 1

Calculate the first term

For n=1

b_1=(1)^2+3=4

step 2

Calculate the second term

For n=2

b_2=(2)^2+3=7

step 3

Calculate the third term

For n=3

b_3=(3)^2+3=12

step 4

Calculate the fourth term

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b_4=(4)^2+3=19

therefore

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4 0
3 years ago
The game of Connex contains one 4-unit piece, two identical 3-unit pieces, three identical 2-unit pieces and four identical 1-un
Aleks [24]

Answer: 277 ways

Step-by-step explanation:

Let’s start bycreating 10-unit pieces using the 4-unit piece.

The arrangements are:

1). 4-3-3 (3 permutations)

2). 4-3-2-1 = 4! = 24 permutations.

3). 4-3-1-1-1 (5*[4!/(3!1!)]

= 5*4

= 20permutations

4). 4-2-2-2 (4 permutations)

5). 4-2-2-1-1 (5 *[4!/(2!2!)]

= 5*6

= 30 permutations

6). 4-2-1-1-1-1(6*[5!/(4!1!)]

= 6*5

= 30 permutations

Let’s-consider the arrangements using one or more3-unit pieces and no 4-unit piece:

7). 3-3-2-2 (4!/(2!2!)

8). 3-3-2-1-1 (5*(4!/(2!2!)

= 5*6

= 30 permutations.

9). 3-3-1-1-1-1 (6!/(4!2!) = 0

10). 3-2-2-2-1 (5*4!/(3!1!)

= 5*4

= 20permutations

11). 3-2-2-1-1-1 (6*5!/(3!2!)

= 6*10

= 60 permutations

Finally we would look at the arrangements using only 1-and 2-unit pieces:

12). 2-2-2-1-1-1-1 (7!/(4!3!)

= 35 permutations

add them all up:

(3 + 24 + 20 + 4) + (30 + 30 + 6 + 30) + (15 + 20 + 60 + 35)

=51 + 96 + 130

= 277ways

5 0
2 years ago
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