Answer:
x^2+y^2-32x+24y+375=0
Step-by-step explanation:
Equation of circle with given centre (h,k) and radius=r is
(x-h)^2+(y-k)^2=r^2
Given centre are=(16, - 12) and radius= 5
So equation of circle=
(x-16)^2+(y- -12)^2=5^2
x^2-32x+256+y^2+24y+144=25
x^2+y^2-32x+24y+375=0
Answer
Answer:
Step-by-step explanation:
Given is a triangle RST and another triangle R'S'T' tranformed from RST
Vertices of RST are (0, 0), (negative 2, 3), (negative 3, 1).
Vertices of R'S'T' are (2, 0), (0, negative 3), (negative 1, negative 1).
Comparing the corresponding vertices we find that x coordinate increased by 2 while y coordinate got the different sign.
This indicates that there is both reflection and transformation horizontally to the right by 2 units
So first shifted right by 2 units so that vertices became
(2,0) (0,3) (-1,1)
Now reflected on the line y=0 i.e. x axis
New vertices are
(2,0) (0,-3) (-1,-1)
4.6 - 3.9= .7cm which is 7mm
Answer:
D. 2x
Step-by-step explanation:
x · 1 + x/1
= x + x
= 2x
