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tatuchka [14]
3 years ago
14

Equation by elimination-4x-9y=20-2x-9y=-24

Mathematics
1 answer:
storchak [24]3 years ago
5 0
I'm not 100% sure this is right but I think this is how you do it

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Solve for x. <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B2%7D%20%20%3D%20%20-%207" id="TexFormula1" title=" \frac{
weeeeeb [17]

Answer:

x = -14

Step-by-step explanation:

\frac{x}{2} = -7

multiply 2 on both sides

the 2's cancel out on the fraction side, leaving x = -7(2)

multiply -7 and 2 to get -14

x = -14

4 0
3 years ago
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Allen is traveling 65 MPh. how many hours will it take for him to travel 585 miles?
FromTheMoon [43]
You would divide 585 by 65 to find rate he's going by, than multiply.  <span />
4 0
4 years ago
CHECK MY WORK PLEASE AND ANSWER SOME QUESTION!!!!!!!! ASAP
Lisa [10]

1.

g > 6.4

<h3>Answer: A. 7 > 6.4</h3>

2.

y + 2 > 8     <em>subtract 2 from both sides</em>

y > 6

<h3>Answer: D. 7 > 6</h3>

3.

6 > z(10 - z)

A. z = 0 → 6 > 0(10 - 0) → 6 > 0 CORRECT

B. z = 1 → 6 > 1(10 - 1) → 6 > 1(9) → 6 > 9 FALSE

C. z = 2 → 6 > 2(10 - 2) → 6 > 2(8) → 6 > 16 FALSE

D. z = 3 → 6 > 3(10 - 3) → 6 > 3(7) → 6 > 21  FALSE

<h3>Answer: A. 0</h3>

4.

The list of factors of 24:

1, 24, 2, 12, 3, 8, 4, 6

<h3>Answer: D. {1, 2, 3, 4, 6, 8, 12, 24}</h3>
6 0
3 years ago
Two trains leave a city at 3 P.M. One train goes east at a constant rate of 70 mph. The other goes west at a rate of 62 mph. How
andrey2020 [161]

Answer:

4 hours

Step-by-step explanation:

The general formula for distance, rate and time is:

d = rt, where distance is the product of rate multiplied by time

Given that one train is moving at a rate of 70 mph and one is moving at a rate of 62 mph in the opposite direction, the combined distance over time is equal to 528 miles.  Using the variable 't' for time:

70t + 62t = 528

Combine like terms: 132t = 528

Divide both sides by 132: 132t/132 = 528/132  or t = 4 hours

8 0
3 years ago
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Is 12ft greater than or less than or equal than 4yds
s2008m [1.1K]
Greater Hope this helps 
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