Help me pleeeeeeaaaseeee

Mathematics

1 answer:

Gelneren [198K]3 years ago

8 0

Answer:

I'm hoping the answer should be D. 9 units.

You might be interested in

The general solution of 2 y ln(x)y' = (y^2 + 4)/x is

Sav [38]

Replace $y'$ with $\dfrac{\mathrm dy}{\mathrm dx}$ to see that this ODE is separable:

$2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}$

Integrate both sides; on the left, set $u=y^2+4$ so that $\mathrm du=2y\,\mathrm dy$ ; on the right, set $v=\ln x$ so that $\mathrm dv=\dfrac{\mathrm dx}x$ . Then

$\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v$

$\implies\ln|u|=\ln|v|+C$

$\implies\ln(y^2+4)=\ln|\ln x|+C$

$\implies y^2+4=e^{\ln|\ln x|+C}$

$\implies y^2=C|\ln x|-4$

$\implies y=\pm\sqrt{C|\ln x|-4}$

4 0

3 years ago

PLS HELP ME ASAP WITH 42!! (MUST SHOW WORK!!) + LOTS OF POINTS!! *best if show picture with work!!*

ddd [48]

I thought this would be simple, as I'm familiar with algebra and not really "The constant of proportionality," but I will do my best.

So this said "Constant of proportionality," is referring to basically the answers for the equation when X equals certain numbers.

Make a table of different answers when you plug in X and you get the 'Constant of proportionality.'

y = 2.5x + 3
y = 2.5(1) + 3
y = 2.5 + 3
y = 5.5

Since we plugged in 1 for X and got 5.5 for Y, our input and output is (1, 5.5)

Replace X for a different value, and you will get a bunch of different numbers that will in essence be your function inputs and outputs. Make a table of these and you have your answer.

EXAMPLE -
-= x =- -= y =-
-= 1 =- -= 5.5 =-
-= 2 =- -= 8 =-
-= 3 =- -= 11.5 =-
-= 4 =- -= 13 =-

So there you have it. I hope this helps! If you have any further questions, don't hesitate to ask.

3 0

3 years ago

Use the reference angles to find the exact value of the expression cot -11 pi/6. Do not use a calculator

laiz [17]

Answer:

$\sqrt{3}$